Answer:
The width will be 
Step-by-step explanation:
Thinking process:
Let the model be:

factoring out 4 gives:

Factorizing the expression in the parentheses gives:

Therefore, since the expression in the parentheses cannot be factorized further, the expression is:

Answer:
To find distance use this equation and plug the variables you have in it.
Equation: Distance=Rate×Time
Answer:
I know u saw me before but the answer is B hope it helps! =)
So... hmmm if you check the first picture below, for 2)
we could use the proportions of those small, medium and large similar triangles like

now.. for 3) will be the second picture below
16 over 3 is the answer u write the numerator above the denominator 6 over 1 minus 2 over 3 6 times 3 over 1 x3 minus 2 over 3 u get 18 minus 2 over 3 and subtract 18 and 2 u get 16 over 3