The domain is all the numbers of which the inputs can be put. Here, we have a graph, which simplifies things. We just need to look at the x-values of the graph, or the horizontal line. The graph extends both negatively and positively. Thus since the graph extends both ways (right and left) forever, the answer would be D, or all real numbers.
Answer:
A
Step-by-step explanation:
O = 26.6
P is a right angle so:
P = 90
angles PQO = 180
To determine Q: triangle total - (P + O)
180 - (90 + 26.6)
180 - 116.6 = 63.4
Q = 63.4
To determine side lengths: a^2 + b^2 = c^2
4^2 + b^2 = c^2
*Variable c is always hypotenuse*
Need more information so find either b or c through SOH, CAH, TOA
SOH: sine = opposite/hypotenuse
CAH: cos = adjacent/hypotenuse
TOA: tan = opposite/adjacent
tan26.6/1 = b/4
Cross multiply
1 × b = 4 × tan26.6
b = 4tan26.6
b = 2.003050791
b is about 2
b = PQ
PQ = 2
Plug b value into pythagorean theorm
4^2 + 2^2 = c^2
16 + 4 = c^2
20 = c^2
square root of 20 = square root of c^2
4.47213.... = c
c is about 4.47
c = QO
Step-by-step explanation:
360 - 126 =234
234 ÷3x
x = 78
Required potynomial = (x -5)(x - 3 - 2i)(x - 3 + 2i) = (x - 5)(x^2 - 6x + 13) = x^3 - 6x^2 + 13x - 5x^2 + 30x - 65 = x^3 - 11x^2 + 43x - 65
Answer:
The length of the rectangle is 18 cm
The width of the rectangle is 6 cm
Step-by-step explanation:
Let
x-----> the length of the rectangle
y----> the width of the rectangle
we know that
The perimeter of the rectangle is
we have
so
------> equation A
------> equation B
Substitute equation B in equation A and solve for y
48=2(2y+6+y)
48=2(3y+6)
48=6y+12
6y=48-12
y=36/6=6 cm
Find the value of x
x=2(6)+6=18 cm
The area of the rectangle is
A=xy
A=18*6
A=108 cm^2
