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beks73 [17]
3 years ago
5

carley beat the school record for the 400 meter run by 1.3 seconds. if she ran the race in 55.7 seconds what was the record?

Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

If Carley ran the 400 meter run in a total of 55.7 seconds and she beat the record by 1.3 seconds, you would add 55.7 and 1.3

55.7+1.3= 57 seconds

The past school record for the girls 400 meter run was 57 seconds

Hope this helps ;)

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Consider the following game, played with three standard six-sided dice. If the player ends with all three dice showing the same
ddd [48]

Answer:

a

 P(A) =  \frac{1}{36}

b

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From the question we are told that

   The  number of dice is  n  =  3

Generally  for all three dice to show the same number the second and the third dice must have the same outcome  as the outcome of the first dice.

This means that the number of outcome the first die can  have is  6  (6 sides), the number of outcome which the second and the third dice can have is  1 (they must match the first )

So the probability that all three dice show the same number on the first roll is mathematically represented as

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=>   P(A) =  \frac{1}{36}

Generally for two of the three dice show the same number after the first roll then the number of outcome for  one of the  dice would be is  6 , the number of outcome for another one must be   1(i.e it must match the first ) , the number of outcome for the remaining one must be   5 (i.e it can show any of the remaining  5  sides which the first and second dice are not showing )

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     N  =  ^3C_2

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      N  =  ^3C_2  = 6

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=>    P(K) =  \frac{1}{6} * \frac{15}{36}  +  \frac{5}{6} *  \frac{1}{6} * \frac{15}{36}

=>  P(K)= \frac{165}{1296}

So the probability that the player wins, conditioned on exactly two of the three dice showing the same number after the first roll is mathematically represented as  

    P(U) =  \frac{\frac{165}{1296}}{\frac{15}{36} }

=>  P(U) = \frac{11}{36}

     

 

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