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beks73 [17]
3 years ago
5

carley beat the school record for the 400 meter run by 1.3 seconds. if she ran the race in 55.7 seconds what was the record?

Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

If Carley ran the 400 meter run in a total of 55.7 seconds and she beat the record by 1.3 seconds, you would add 55.7 and 1.3

55.7+1.3= 57 seconds

The past school record for the girls 400 meter run was 57 seconds

Hope this helps ;)

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Complete the table below by calculating the commission and adding it to the price of the stock.
asambeis [7]

We calculate the commission and adding it to the price of the stock to get total cost.

No       Price              Total Commission                         Total cost

100    $26.25         0.06 x $2,625 = $157.50     2625 + 157.50 =2782.5

100    $19.32         0.06 x $1,932 = $115.92         1932 + 115.92 =2047.92

40     $9.77          0.06 x $390.80 = $23.45      390.80 + 23.45= 414.25

200   $5.39          0.06 x $1,078 = $64.68        1,078 + 64.68 = 1142.68      

100    $33.44       0.06 x $3,344 = $200.64      3,344 + 200.64 = 3544.64


3 0
4 years ago
Read 2 more answers
A rectangular prism shaped fish tank is 14 in tall the perimeter of the base is 96 in the length of the base is 3 times the widt
Alla [95]

Using the given information find the length and width of the base:

Perimeter = 2L + 2W

L = 3W

Replace L in the first equation:

Perimeter = 2(3W) + 2w

96 = 2(3W) +2W

Simplify:

96 = 6W +2W

96 = 8w

Divide both sides by 8:

w = 96 / 8

w = 12

The width is 12 inches.

The length = 3 x 12 = 36 inches.

Volume = L x W X H

Volume = 36 x 12 x 14

Volume = 6,048 cubic inches.

5 0
3 years ago
I will give brainliest to the person who does this first
WITCHER [35]

1. 8a+24

2. .12e

ill edit it when get the other answers

Brainiest? pls

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2 years ago
Hello it's mathhhhhh
yaroslaw [1]

Answer:

36

Step-by-step explanation:

4*6=24

3*4=12

24+12=36

8 0
3 years ago
Read 2 more answers
Someone help me please and thank you!! ASAP :(
pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

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3 years ago
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