The value of 
exists 1061208.
<h3>How to estimate the value of
?</h3>
Let us rewrite as 
Now utilizing the identity 
, we get
a = 100 and b = 2 then substitute the values of a and b then
![(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]](https://tex.z-dn.net/?f=%28100%2B2%29%5E3%3D100%5E3%2B2%5E3%2B%5B%283%5Ctimes100%5Ctimes2%29%28100%2B2%29%5D)
= 1000000 + 8 + (600 × 102)
= 1000000 + 8 + 61200
= 1061208
Hence, 
Therefore, the value of exists 1061208.
To learn more about cubic polynomial equation refer to:
brainly.com/question/28181089
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Multiple 3 by 7 it would be 21 so 21 over 8 evaluate it .it will be2.625 the answer is 2.625 hope this helps you good luck
Find the distance between the points t(13, 1.6)t(13, 1.6) and v(5.4, 3.7)v(5.4, 3.7).
1
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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:
Thus the distance between points t(13, 1.6) and v(5.4, 3.7) is found using the formula as:
Opening brackets gives;
4-8v=-8v+4
Putting like terms together;
4-4=-8v+8v
0=0
There is no solution thus.
Step-by-step explanation:
The system of equations for eq 1 which is 3x + y = 118 represents the Green High School which filled three buses(with a specific number of students identified as x) and a van(with a specific number of students identified as y) with a total of 118 students.
for eq 2; 4x + 2y = 164; represents Belle High School which filled four buses(with a specific number of students identified as x) and two vans(with a specific number of students identified as y) with a total of 164 students.
The solution represents the specific number of students in the buses and vans in eq1 and eq 2 with x being 36 students and y being 10 students.
substituting 36 for x and 10 for y in eq 1;
3(36) + 10 = 108 + 10 = 118 total students for Green High School
substituting 36 for x and 10 for y in eq2;
4(36) + 2(10) = 144 + 20 = 164 total students for Belle High school
