3/4 I believe since 6 1/4- 51/2 is 3/4
Y = -0.01x^2 + 0.5x + 3
when the height y = 8
-0.01x^2 + 0.5x + 3 = 8
-0.01x^2 + 0.5x - 5 = 0
x = 13.82 and x = 36.18 so the ball is at least 8 ft high from 13.82 and 36.18 feet inclusive.- from the player.
If the player is 30 ft from the net then the ball is likely to go over the net.
Answer:
(f/g)(4) = 3
(f + g)(4) = 28
Step-by-step explanation:
(f/g) = 
(f + g) = 
Simply plug in 4 for x in both equations to find you answer!
Answer:
Step-by-step explanation:
the answer is either d or b but i think its d