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ASHA 777 [7]
3 years ago
5

Find an equation to the line tangent to y = 5 + |x – 2| at the coordinate (2, 5) pls answer

Mathematics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

Step-by-step explanation:

Finding an equation of a tangent line to that function requires that we find the derivative of the function at that point. Since this is an absolute value function with its cusp at (2, 5), the function is not differentiable here.

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John can reach 60 centimeters above the top of his head. If John is 2 meters tall, how high can he reach?
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He can reach 2.6 meters or 260 centimeters
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A quadrilateral has angles that measure 74°, 93°, and 117°.
Lana71 [14]

Answer:

D

Step-by-step explanation:

74 + 93 + 117= 284

360 - 284 = 76

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3 years ago
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What is the result of the mathematical expression of 1b^3+1b?
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

b^3+b

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3 years ago
Let the sample size of leg strengths to be 7 and the sample mean and sample standard deviation be 630 watts and 32 watts, respec
Colt1911 [192]

Answer:

a. There is_<u><em>sufficient</em></u> evidence that the leg

C. 0.010 < P-value < 0.025

b. Power of test = 1- β=0.2066

c. So the sample size is 88

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0 : u1= u2 against Ha : u1 > u2 This is a right tailed test

Here n= 7 and significance level ∝= 0.005

Critical value for a right tailed test with 6 df is 1.9432

Sample Standard deviation = s= 32

Sample size= n= 7

Sample Mean =x`= 630

Degrees of freedom = df = n-1= 7-1= 6

The test statistic used here is

Z = x- x`/ s/√n

Z= 630-600 / 32 / √7

Z= 2.4797= 2.48

P- value = 0.0023890 > ∝ reject the null hypothesis.

so it lies between 0.010 < P-value < 0.025

b) Power of test if true strength is 610 watts.

For  a right tailed test value of z is = ± 1.645

P (type II error) β= P (Z< Z∝-x- x`/ s/√n)

Z = x- x`/ s/√n

Z= 610-630 / 32 / √7

Z=0.826

P (type II error) β= P (Z< 1.645-0.826)

= P (Z> 0.818)

= 0.7933

Power of test = 1- β=0.2066

(c)

true mean = 610

hypothesis mean = 600

standard deviation= 32

power = β=0.9

Z∝= 1.645

Zβ= 1.282

Sample size needed

n=( (Z∝ +Zβ )*s/ SE)²

n=  ((1.645+1.282) 32/ 10)²

Putting the values  and solving we get 87.69

So the sample size is 88

5 0
3 years ago
During a sale a store offered a 40% discount on a particular camera that was originally price at $450 after the sale the discoun
Artemon [7]

£378


$450×0.6=$270.

$270×1.4=$378

3 0
3 years ago
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