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riadik2000 [5.3K]

2 years ago

8

Idek the answer, can someone help me pls

1 answer:

Sunny_sXe [5.5K]2 years ago

3 0

Answer:

A) 1/6

Step-by-step explanation:

There are six sides on a dice and one number 3.

That means that you have a chance in one of six roles to get a 3 one time.

This may not be very clear so you can ask more questions in the comments!

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OLEGan [10]

Answer:

20909.09 grams

Step-by-step explanation:

$\frac{46 \: lb}{1} \times \frac{1 \: kg}{2.2 \: lb} \times \frac{1000 \: g}{1 \: kg} = \\ \frac{46 \: lb}{2.2 \: lb} \times \frac{1 \: kg}{1} \: \times \frac{1000 \: g}{1 \: kg} = \\\frac{230 \: }{11 \:} \times \frac{1 \: kg}{1 \: kg \:}\times \frac{1000 \: g}{1 \:} = \\\frac{230 \: }{11 \:} \times \frac{1}{1}\times \frac{1000 \: g}{1 \:} = \\\ \frac{230}{11}g \times 1g \times \: 1000g$

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A random sample of 70 printers discovered that 25 of them were being used in small businesses. find the 95% limit for the popula

kvasek [131]

Answer:

The sample proportion of printers used in small business is:

$\hat{p}=\frac{25}{70}=0.3571$

The 95% confidence interval for the population proportion of printers that are used in small businesses is:

$\hat{p} \pm z_{\frac{0.05}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n} }$

Where:

$z_{\frac{0.05}{2}}=1.96$ is the critical value at 0.05 significance level

$\therefore 0.3571 \pm 1.96 \sqrt{\frac{0.3571(1-0.3571)}{70} }$

$0.3571 \pm 0.1122$

$\left ( 0.3571 - 0.1122, 0.3571 + 0.1122 \right)$

$\left(0.245,0.469 \right)$

Therefore, the 95% confidence interval for the population proportion of printers that are used in small businesses is (0.245 , 0.469)

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2 years ago