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maks197457 [2]
3 years ago
9

Find a polynomial of degree n that has only the given zero(s). x= -7,1,2 n=4

Mathematics
1 answer:
saveliy_v [14]3 years ago
4 0
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HELP ME (for b show work pls thank you!
emmasim [6.3K]
For A put 160 (division sign} 4. 
For B put -40 
5 0
3 years ago
What is the mean of this set 18,21,20,14,17
konstantin123 [22]

Answer: 18

Step-by-step explanation:

Add them all up

18+21+20+14+17=90

Divide by 5 since that is how many numbers there are

90/5=18

6 0
3 years ago
Read 2 more answers
How much should a family deposit at the end of every 6 months in order to have $4000 at the end of 3 years? The account pays 5.9
ra1l [238]

We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:

PV_{ord}=C(\frac{1-(1+i)^{-kn}}{\frac{i}{k}})

Where:

\begin{gathered} C=\text{ payments each period} \\ i=\text{ interest rate} \\ n=\text{ number of periods} \\ k=\text{ number of times the interest is compounded} \end{gathered}

Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:

\frac{5.9}{100}=0.059

Now we substitute the values:

PV_{ord}=4000(\frac{1-(1+0.059)^{-2(3)}}{\frac{0.059}{2}})

Now we solve the operations, we get:

PV_{\text{ord}}=39462.50

Therefore, the present value must be $39462.50

8 0
1 year ago
(m-3)/(7)=(m)/(m+8) Solve the proportion.
ExtremeBDS [4]

Answer: m=6, m=-4

Step-by-step explanation:

To solve this proportion, we have to cross multiply.

\frac{m-3}{7} =\frac{m}{m+8}

(m-3)(m+8)=7m

Now that we have cross multiplied, we actually need to FOIL the left side to expand the equation.

m^2+8m-3m-24=7m

Combine like terms.

m^2+5m-24=7m

We can move all terms to one side and then solve for m.

m^2-2m-24=0

We can actually factor this to:

(m-6)(m+4)=0

We set each factor equal to 0 to find m.

m-6=0

m=6

m+4=0

m=-4

6 0
3 years ago
Under what circumstances are two nonright triangles congruent?
soldier1979 [14.2K]
If these are the given choices of the above problem,

a. one side and one angle are equal. 
<span>b.three sides are equal </span>
<span>c.two angles are equal </span>
<span>d. three angles are equal

Two non-right triangles are congruent when B. THREE SIDES ARE EQUAL.

Two triangles are congruent if:
1) All corresponding sides are equal (SSS)
2) A pair of corresponding sides and the included angle are equal (SAS)
3) A pair of corresponding angles and the included side are equal (ASA)
4) A pair of corresponding angles and a non-included side are equal (AAS)</span>
3 0
3 years ago
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