Answer:
Explanation:
If L(D1) = L(D2), the D has every state being final
If L(D1) = L¯(D2), the D has every state being final
If L(D1) = ∅, then L(D) = L(D2).
If L(D1)=Σ, L(D) = L(D2)
Answer:
# Code in Python
dictionary={'A':1,'B':2,'C':3,'D':4}
other_dictionary={}
for keys in dictionary:
if dictionary[keys]&1==1:
temp=dictionary[keys]*dictionary[keys]-10*10
other_dictionary[keys]=temp
else:
other_dictionary[keys]=dictionary[keys]
print(other_dictionary)
assert other_dictionary
Explanation:
- Initialize a sample example dictionary and other_dictionary.
- Do a binary comparision for checking odd number
.
- Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
- For even: store the original value (from dictionary).
What dose osha means please
Answer:
A. Sandboxing
Explanation:
The best solution to apply for this task would be Sandboxing. This is a software management strategy that isolates applications from critical system resources and other programs. In doing so you effectively add a secondary security layer on top of the application in order to prevent any and all malware from entering and damaging your overall system. Thus effectively reducing the risk.
