Answer:
6.75g
Step-by-step explanation:
The first step is converting everything to grams, by rules of three. Then we add.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
Unit conversion problems, like this one, is an example of a direct relationship between measures.
First step: 0.0025kg to g
Each kg has 1000g, so:
1kg - 1000g
0.0025kg - xg
x = 1000*0.0025 = 2.5g
0.0025kg = 2.5g
Second step: 1750 mg
Each g has 1000mg, so:
1g - 1000mg
xg - 1750mg
1000x = 1750
x = 1.75g
1750 mg = 1.75g
2.25g - OK
Third step: 825,000 μg to g
Each g has 1,000,000 ug, so:
1g - 1,000,000 ug
xg - 825,000 ug
1,000,000x = 825,000
x = 0.25g
825,000 μg = 0.25g
Final step: adding everyting
0.25g + 2.25g + 1.75g + 2.50g = 6.75g
Hello!
The slope intercept form is y=mx+b, where m is the slope and b is the y-intercept.
First, let's find the y-intercept. This is where the line hits the y-axis. Therefore, it hits at 4 on the y-axis, so our y-intercept is 4.
To find the slope, let's find 2 points on our line. Let's use (0,4) and (2,5). We divide the difference in the y-values by the difference in the x-values as shown below.
Therefore, our slope is 2.
Now we plug these values into our equation.
y=2x+4
I hope this helps!
Answer:
So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case
Step-by-step explanation:
For this case we can define the random variable X as the amount of time it takes her to arrive to work and we know that the distribution for X is given by:
And we want to use the empirical rule to estimate the middle 95% of her commute times. And the empirical rule states that we have 68% of the values within one deviation from the mean, 95% of the values within two deviations from the mean and 99.7 % of the values within 3 deviations from the mean. And we can find the limits on this way:
So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case