3 years ago

The length of a rectangle is four times its width. If the perimeter of the rectangle is 60 yd, find its area.

Mathematics

1 answer:

mars1129 [50]3 years ago

3 0

Answer:

Step-by-step explanation:

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If limx→3f(x)=7, which of the following must be true? I. f is continuous at x = 3 II. f is differentiable at x = 3

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Without knowing anything else about $f(x)$ , neither of these need be true.

Suppose

$f(x)=|x-3|+7=\begin{cases}10-x&\text{for }x3\\0&\text{for }x=3\end{cases}$

Then (I) isn't true because, while the limit exists as $x\to3$ and is equal to 7, we have $f(3)=0\neq7$ , so $f(x)$ is not continuous there.

(II) also true because $f(x)$ is not differentiable at $x=3$ ; that is,

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3 years ago

The length of a rectangle is four times its width. If the perimeter of the rectangle is 60 yd, find its area.​

The length of a rectangle is four times its width. If the perimeter of the rectangle is 60 yd, find its area.