Question

ANSWER ASAP!!!!! How many liters of a 10% salt solution must be mixed with 5 liters of a 50% salt solution to give a 20% solution?

Answer 1

The answer this question is 15 liters

Answer 2

Answer:

  15 liters

Step-by-step explanation:

Let v represent the number of liters of 10% solution to be mixed with 5 liters of a 50% solution to obtain a 20% solution. The amount of salt in the final solution is ...

  0.10x +0.50(5) = 0.20(x+5)

  1.5 = 0.10x . . . . . simplify, subtract 1+0.10x

  15 = x . . . . . . . . . multiply by 10

15 liters of 10% solution must be added.