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kolezko [41]
3 years ago
15

Suppose a country has a population of 50 million and projects a growth rate of 4% per year for the next 20 years. What will the

population of this country be in 11 years? (Round your answer to two decimal places.)
Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

The population of this country in 11 years will be 76972702.82

Step-by-step explanation:

The population of this country in 11 years can be calculated using the formula

Population in 11 years =  Starting population x (1+growth rate)^{period}

Thus

Population in 11 years =50000000×(1+0.04)^{11} =76972702.82

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galben [10]

Answer:

The population of the town in 2020  will approx. be 12,039.

Step-by-step explanation:

The initial population in the year 2017 = 10,400

Increase in population every yea r  =  5%

Now, 5% of 10, 400 = \frac{5}{100} \times 10, 400 = 520

Hence, the population in the year 2018 = 10,400 + 520 = 10,920

Now, in the year 2019

5% of 10, 920 = \frac{5}{100} \times 10, 920 = 546

Hence, the population in the year 2019 = 10,920 + 546 = 11,466

Now, in the year 2020

5% of 11,466 = \frac{5}{100} \times 11,466 = 573.3

or, the population in the year 2020 = 11,466  + 573.3 = 12,039.3

The population of the town in 2020  will approx. be 12,039.

6 0
3 years ago
$11.25 is what percent of $375?<br> PLS Help Me!!!
Ivahew [28]

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4 0
3 years ago
Lexy and Lonnel applied to the same university. They looked up the average SAT score of students admitted to that university. Le
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4 0
2 years ago
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8 0
3 years ago
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Goryan [66]

Answer:

301 acres

Step-by-step explanation:

43,000 acres of forest

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0.7% = 0.007

43,000 * 0.007 = 301 acres

7 0
3 years ago
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