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3 years ago

PLEASE HELP!!! BRAINLYEST!!!

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

Using the rule of exponents

$\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$

Note that 8 = 2³, thus

$\frac{2^{5} }{8}$

= $\frac{2^{5} }{2^{3} }$

= $2^{(5-3)}$

= 2²

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-x = -6 <br> please help me

Rasek [7]

Answer:

The answer would be positive 6

Step-by-step explanation:

I know it is -6 because when you solve this you do...

-x = -6

Divide both sides by -6

-x/-6 = -6/-6

the answer would be 6

because a negative divided by a negative is a positive.

Hope this helps have a great day! :)

6 0

3 years ago

PLEASE HELP ME PLEASE HELP

aliina [53]

To grandparents house :
140/56 = 2.5 hours

Return trip :
140/50 = 2.8 hours

Total time : 2.8+2.5 = 5.3 hours

7 0

3 years ago

Read 2 more answers

Plot (25/3) and (42/3) on the number line.

ss7ja [257]

Answer:

Refer to the Attachment

Step-by-step explanation:

Rewriting the fractions in decimal and whole number, we have the following:

$\frac{25}{3} = 8\frac{1}{3} = 8.3$

$\frac{42}{3} = 14$

Thus, 42/3 is on 14 and 25/3 is on 8 and then add 1/3 from 8 going to 9.

Therefore, the points must be plotted as follows:

The blue point indicates the 42/3 while the red point indicates the 25/3.

8 0

3 years ago

Find the circumference and area of a circle with a diameter of 10 inches leave answers in terms of pi

Umnica [9.8K]

Answer:

The circumference is = 10π

The area is = 25π

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-620=\dfrac{749-620}{70-30}(x-30)$

$y-620=\dfrac{129}{40}(x-30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}$

Adding 620 on both sides, we get

$y=\dfrac{129}{40}x-\dfrac{387}{4}+620$

$y=\dfrac{129}{40}x+\dfrac{2480-387}{4}$

$y=\dfrac{129}{40}x+\dfrac{2093}{4}$

We need to find the y-value for $x=57$ .

$y=\dfrac{129}{40}(57)+\dfrac{2093}{4}$

$y=183.825+523.25$

$y=707.075$

$y\approx 707.1$

Therefore, the required linear equation for the given situation is $y=\dfrac{129}{40}x+\dfrac{2093}{4}$ and the average score for persons taking a 57-hour review course is 707.1.

4 0

2 years ago