Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.

- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )

E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
The correct answer for this question would be about $4,467.2 according to my estimation.
If it’s not correct, I’m sorry, but if it is, please mark the brainliest!!
Answer:
-2
Step-by-step explanation:
If we have an equation of the form y = mx +b then the y-intercept is b.
So now here we have y =-x - 2. Therefore b = -2 and we conclude the y-intercept is -2.
Answer:
Step-by-step explanation: I cannot provide an answer due to insufficient evidence.
Answer:
y= -7x -27
Step-by-step explanation: