1. Answer (D). By the law of sines, we have 
in any 
2. Answer (C). The law of cosines, 
accepts up to three sides and an angle as an input.
3. Answer (D). Although this triangle is right, we are not given enough information to uniquely determine its sides and angles - here, we need either one more side or one more angle.
4. Answer (D). Don't get tripped up by answer choice (C) - this is just a rearrangement of the statement of the law of cosines. In choice (D), the signs of 
and 
are reversed.
5. Answer (B). By the law of sines, we have 
Solving gives 
Note that this is the <em>ambiguous (SSA) case</em> of the law of sines, where the given measures could specify one triangle, two triangles, or none at all!
6. Answer (A). Since we know all three sides and none of the angles, starting with the law of sines will not help, so we begin with the law of cosines to find one angle; from there, we can use the law of sines to find the remaining angles.
Answer:
Step-by-step explanation:
Rational numbers:
-are all numbers you can write as a quotient of integers 
, 
-include terminating decimals. For example, 
-include repeating decimals. For example, 
Irrational numbers:
-have decimal representations that neither terminate nor repeat. For example, 
-cannot be written as quotients of integers
There are four s's and two sevens. Two times seven is fourteen and four times s is 4s. So then you have 4s + 14. Subtract 14 from 114 and then divide the quotient by 4. This should get you 25. so then every side is 25, and for the length it's 32 because s=25 and the equation you have says s+7. The dimensions would be 25 plus 25 plus 32 plus 32
The domain is actually the x value of the function, so we need to find the value of x
suppose the width is x, the length is then 3x+5
the area is 50^2 inches, so x(3x+5)=50 => 3x^2+5x-50=0
Factor this quadratic equation: (x-5)(3x+10)=0 =>x=5 or x=-10/3
width can not be negative, so the width is 5
the domain is x=5
Answer:
20.25
Step-by-step explanation:
