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3 years ago

How do I write a fraction that is greater than 1/2 and less then 3/4?

1 answer:

6 0

1/2 = 50%

3/4 = 75%

So something in between that could be 2/3 (which equals 66.67% )

A few others could be: 3/5 ( equals to 60% ) , 7/10 ( equals 70%)

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4x + 1/3 y 2 what is the value of the expression above when x = 2 and y = 3

GenaCL600 [577]

Hoi!

To solve this, first plug in the values for x and y.

x = 2, so anywhere you see x, put 2 in its place.

y = 3, so anywhere you see y, put 3 in its place.

$4(2) + \frac{1}{2}(3)$

4 × 2 = 8

$\frac{1}{2}$ × 3 = $1 \frac{1}{2}$

$8 +1 \frac{1}{2}$ = $9 \frac{1}{2}$

$9 \frac{1}{2}$ is your answer.

4 0

3 years ago

Read 2 more answers

Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu . assum

attashe74 [19]

To solve for the confidence interval for the population mean mu, we can use the formula:

Confidence interval = x ± z * s / sqrt (n)

where x is the sample mean, s is the standard deviation, and n is the sample size

At 95% confidence level, the value of z is equivalent to:

z = 1.96

Therefore substituting the given values into the equation:

Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)

Confidence interval = 3 ± 1.59

Confidence interval = 1.41, 4.59

Therefore the population mean mu has an approximate range or confidence interval from 1.41 kg to 4.59 kg.

6 0

3 years ago

Simplify 5x(3x^2+2x-3)

Tcecarenko [31]

Answer:

$15x^3 +10x^2 - 15x$

Step-by-step explanation:

Hello!

Use the distributive property and multiply like terms.

<h3>Simplify</h3>

$5x(3x^2 + 3x - 3)$
$5x(3x^2) + 5x(2x) + 5x(-3)$
$15x^3 +10x^2 - 15x$

The simplified form is $15x^3 +10x^2 - 15x$ .

4 0

2 years ago

Read 2 more answers

Find the solutions for x when y is equal to 0.<br> y = x2 - 3x -18

denis23 [38]

Y = x² - 3x - 18

When y = 0,

x² - 3x - 18 = 0

<span>(x + 3)(x - 6) = 0
</span>
x = -3 or x = 6

3 0

3 years ago

Write and graph an equation:

Alexxandr [17]

Answer:

y=29*x

Step-by-step explanation:

This problem is a linear function problem. We need at least two points to solve it. After finding two points we will compute the slope and then us the point-slope formula.

If you put 11 gallons of gasoline in your car it will allow you to drive 319 miles, this means that when x= 11 then, y=319. So the first point is (11,319). For the second point you now that if you have no gallons of gasoline then you won't be able to drive so, the second point is (0,0).

Now that we have to points we are able to compute the slope. The formula for the slope is:

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ .