The equidistant point for all three, will be the "centroid" of their triangular locations
thus $\bf \textit{Centroid of a Triangle}
\begin{array}{llll}
Amy
\begin{array}{llll}
(2,3)\\
x_1,y_1
\end{array}\quad Brian
\begin{array}{llll}
(0,7)\\
x_2,y_2
\end{array}\quad Claire
\begin{array}{llll}
(-2,3)\\
x_3,y_3
\end{array}\\ \quad \\\\\\
\left(\cfrac{x_1+x_2+x_3}{3}\quad ,\cfrac{y_1+y_2+y_3}{3}\quad \right)
\end{array} 
$

6 0

2 years ago

A determined gardener has 120ft of deer-resistant fence. She wants to enclose a rectangular vegetable garden in her backyard, an

Pavlova-9 [17]

Answer:

the answer is 123

Step-by-step explanation:

cuz thats wat it is cux i think so

3 0

3 years ago

Find the volume of each figure, round to nearest tenth

jenyasd209 [6]

Answer
Height:8km
Radius:4km
Diameter:8
Volume:402.12

3 0

2 years ago

Please Help!

Lisa [10]

We know that

in the right triangle
sin x=opposite side angle x/hypotenuse
opposite side angle x=66 mm
hypotenuse=79 mm
so
sin x=66/79
x=arc sin (66/79)-------> x=56.66°-------> x=56.7°

the answer is
x=56.7°

7 0

3 years ago