2^2x=5^x−1
Take the log pf both sides:
ln(2^2x) = ln(5^x-1)
Expand the logs by pulling the exponents out:
2xln(2) = (x-1)ln(5)
Simpligy the right side:
2xln(2) = ln(5)x - ln(5)
Now solve for x:
Subtract ln(5)x from both sides:
2xln(2) - ln(5)x = -ln(5)
Factor x out of 2xln(2)-ln(5)x
x(2ln(2) - ln(5)) = -ln(5)
Divide both sides by (2ln(2) - ln(5))
X = - ln(5) / (2ln(2) - ln(5))
9514 1404 393
Answer:
A. 7 seconds
Step-by-step explanation:
We assume your factored equation is something like ...
h(t) = -16t(t -7)(t +2)
The time it takes the ball to reach the ground is the positive value of t that makes a factor zero:
t -7 = 0 ⇒ t = 7
The ball will land on the ground in 7 seconds.
Answer:
add all the angles
Step-by-step explanation:
140+82+78
43 times 68.
43
x68
8 times 3 is 24. Bring the 2 over the 4.
8 times 4 is 32. Add 4. Equals 36.
Answer so far is 364.
Add a 0 before answering.
3 times 6 is 18. Bring the 1 over the 4.
4 times 6 is 24. Add 4. Equals 28.
Answer so far is 288
Add 364 + 288
Final answer is 652.
Answer:
y = 3/2x + 15
Step-by-step explanation:
change f(x) to 'y='
interchange 'x' and 'y' then solve for 'y':
y = 2/3x - 10
x = 2/3y - 10
x+10 = 2/3y
multiply each side by 3/2 to get:
y = 3/2x + 15
