Answer:
56.47%
Explanation:
Determine the efficiency of the Engine
Given data : T1 (k) = 325, P1 (kpa) = 185,
V1 (cm^3) = 410 , r = 8, T3(k) = 3420
speed ( RPM) = 4800
USING THIS FORMULA
efficiency ( <em>n </em>) =
= 1 - = 1 - (1/8^1.4-1 )
= 0.5647 = 56.47%
Answer:
transmitter hope thus helped!
Explanation:
Answer: Forward So it's D
Answer:
Dimension of specific heat will be
Explanation:
We know that heat , Q is heat generated, m is mass, c is specific heat and is temperature difference
From formula we can write
Now unit of Q is joule or N-m
Newton can be written as
So unit of Q is
For dimension we use M for kg, L for meter(m) ,T for sec and for temperature
So dimension of Q is
So dimension of specific heat will be
Answer:
Explanation:
Heat dissipated by 26 people per second
= 26 x 360 x 1000 / (60 x 60)
= 2600 J
Heat dissipated by bulbs per second
= 15 x 40
= 600 J
Heat dissipated by fans per second
200 J
Heat dissipated by air coming in
= 200 x 10 x 1000 / (60 x 60)
=555.55 J
Heat gain by walls
= 5000 x 1000 / (60 x 60)
= 1388.88 J
Total heat gain per second
= 2600 + 600+200+555.55
= 3955.55 J
Capacity of air-conditioner required
= 3955.55 J/s
= 3.9 kJ/s
= 3.9kW
= 4 kW