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3 years ago

(D) 13. Describe the differences between an impact socket and a conventional socket.

Engineering

1 answer:

docker41 [41]3 years ago

3 0

Answer:

The wall of an impact socket is around 50% thicker than that of a regular socket, making it suitable for use with pneumatic impact tools, whereas regular sockets should only be used on hand tools.

Explanation:

This allows the socket to remain securely attached to the impact wrench anvil, even under high stress situations.

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Consider a steady isentropic airflow through a convergent channel with an inletto-exit cross section area ratio of 2. If the inl

Nina [5.8K]

Answer:

for m1=0.2

M2=0.4

for m1=2.5

M2=5

1= channel input

2.channel output

Explanation:

Hello!

To solve this problem follow the steps below!

1.As it is an isentropic system, it means that the temperature of the fluid remains constant, so the volumetric flow is the same, remember that this is calculated by calculating the product between the velocity and the area.

V1A1=V2A2

1= channel input

2.channel output

We can divide both sides of the equation by the speed of sound(V)

$\frac{V1}{V}A1= \frac{V2}{V}A2$

2. The mach number is defined as the ratio between the speed of a fluid and the speed of sound,

we rearrange the equation

M1A1=M2A2

$\frac{M1A1}{A2} =M2$

3.Now considering that the channel is convergent and that the ratio between the areas is 2, we have the following equation (A1 / A2 = 2)

M1(2)=M2

4.Finally we solve for the number of mach indicated (0.2 and 2.5)

for m1=0.2

0.2(2)=M2=0.4

for m1=2.5

2.5(2)=M2=5

8 0

3 years ago

You plan to install an active, liquid-based solar heating system for hot water. There are four candidate collector systems. Your

olchik [2.2K]

Solution:

The given formula,

$x=F_{R} U_{L} \times \frac{P l}{F R_{1}} \times\left(T_{r e f}-\bar{T}_{a}\right) \Delta t \times \frac{A_{c}}{L}$

$y=F_{R}(\tau \alpha)_{n} x \frac{F_{R}^{\prime}}{F_{R}} \times \frac{(\bar{\tau} d)}{(T d)_{n}} \times \bar{H}_{T} N \times \frac{A C}{L}$

$\frac{x}{y}=\frac{ u_{L} \times\left(T_{x t}-\bar{T}_{a}\right) \times \Delta t}{\left(\tau_{x}\right)_{h} \times\left(\frac{\bar{\tau}_{d}}{\left.| \tau_{d}\right)_{n}}\right) \times \bar{H}+N}$

From the table,

$1) $\quad x=2 \cdot 87, \quad y=0.96$\\$\frac{x}{y}=\frac{2187}{0.96}$22895\\\\2) $x=3 \cdot 466 \cdot y=6 \cdot 998$\\$\frac{x}{y}=\frac{3 \cdot 466}{0.898}$$=3 \cdot 4729$$

$3$x=3 \cdot 229, y=1 \cdot 08$\\$\frac{x}{x}=\frac{3 \cdot 229}{1 \cdot 08}$\\=2.9898\)\\\\4) $x=6.525, y=1.094$\\$\frac{x}{y}=\frac{5.625}{1.094}$\\=5.0502$

8 0

4 years ago

Scissors is to cut as?

lidiya [134]

Answer:

yes...? uhm I don't know what this means

6 0

3 years ago

A 40 mph wind is blowing past your house and speeds up as it flows up and over the roof. If the elevation effects are negligible

Finger [1]

The pressure at the point on the roof where the speed is 60mph is 14.66 psi

<u>Explanation:</u>

The question follows Bernoulli's equation

P1 + 1/2 ρ V1² = P2 + 1/2 ρ V2²

V1 = 40 X 5280 / 3600 = 58.7 ft/s

V2 = 60 X 5280 / 3600 = 88 ft/s

P2 = P1 + 1/2 ( 0.00238 ) [(58.7)² - (88)²]

P2 - P1 = -5.12lb/ft²

The negative pressure created tends to lift the roof.

We know,

P1 = 14.7 psi = 2116.8 lb/ft²

P2 = 2116.8 - 5.12 lb/ft²

P2 = 2111.68 lb/ft²

P2 = 14.66 psi

Therefore, the pressure at the point on the roof where the speed is 60mph is 14.66 psi

7 0

3 years ago

Carbon dioxide enters a compressor at 100 kPa and 300 K at a rate of 0.2 kg/sec and exits at 600 kPA and 450 K. Determine the po

NemiM [27]

Answer:

Explanation:

attached below

8 0

3 years ago