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AleksandrR [38]
2 years ago
6

(D) 13. Describe the differences between an impact socket and a conventional socket.

Engineering
1 answer:
docker41 [41]2 years ago
3 0

Answer:

The wall of an impact socket is around 50% thicker than that of a regular socket, making it suitable for use with pneumatic impact tools, whereas regular sockets should only be used on hand tools.

Explanation:

This allows the socket to remain securely attached to the impact wrench anvil, even under high stress situations.

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A thick steel slab ( 7800 kg/m3 , c 480 J/kg K, k 50 W/m K) is initially at 300 C and is cooled by water jets impinging on one o
Nutka1998 [239]

Answer:

1791 secs  ≈ 29.85 minutes

Explanation:

( Initial temperature of slab )  T1 = 300° C

temperature of water ( Ts ) = 25°C

T2 ( final temp of slab ) = 50°C

distance between slab and water jet = 25 mm

<u>Determine how long it will take to reach T2</u>

First calculate the thermal diffusivity

∝  = 50 / ( 7800 * 480 ) = 1.34 * 10^-5 m^2/s

<u>next express Temp as a function of time </u>

T( 25 mm , t ) = 50°C

next calculate the time required for the slab to reach 50°C at a distance of 25mm

attached below is the remaining part of the detailed solution

5 0
3 years ago
Before finishing and installing a shelved cabinet you just constructed, you need to check the
Greeley [361]

Answer:

Carpenter's square

Explanation:

The most common hand tool used to measure or set angles with its application extending to setting angles of roofs and rafters. Another name of a Carpenter's square is a framing square.

Other hand tools that are used to measure angles are;

  • The combination square that allows a user to set both 90°  and 45° angles
  • A Bevel that allows users to set any angle they like.
  • A Protractor that resembles a bevel but its marks are marked in an arc.
  • An electromagnetic angle finder which gives a reading according to the measure of the arms adjusted by the user.
7 0
3 years ago
A cylindrical brass rod has a length of 5.00cm extending from a holder and a diameter of 4.50mm. Its Young's modulus is 98.0GPa.
Galina-37 [17]

Answer:

elongation of the brass rod is 0.01956 mm

Explanation:

given data

length = 5 cm = 50 mm

diameter = 4.50 mm

Young's modulus = 98.0 GPa

load = 610 N

to find out

what will be the elongation of the brass rod in mm

solution

we know here change in length formula that is express as

δ = \frac{PL}{AE}    ................1

here δ is change in length and P is applied load  and A id cross section area and E is Young's modulus and L is length

so all value in equation 1

δ = \frac{PL}{AE}  

δ = \frac{610*50}{\frac{\pi}{4} * 4.50^2 * 98*10^3}  

δ = 0.01956 mm

so elongation of the brass rod is 0.01956 mm

7 0
3 years ago
Select the correct answer. Jennifer, a construction manager at a construction firm, has to hire several contractors and subcontr
Ymorist [56]
A. Quality management
7 0
3 years ago
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The "Big Dig" was the nickname of the civil engineering project that redesigned the highway Infrastructure for the city of
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Geotechnical since it’s geologicaly based
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3 years ago
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