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alukav5142 [94]
3 years ago
13

Solve by Completing the Square

Mathematics
1 answer:
guajiro [1.7K]3 years ago
4 0
You have to do -b/2a and put a square at the end of each =. You have to make it equal to 0 first though
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The table shows the American League batting champions for the years 1999–2003. The sum of these five batting averages is 1.754.
fgiga [73]
The answer is <span>A. .357 + .372 + .350 + .349 + x = 1.754; .326 
</span>
x1 - average of <span>1999 Nomar Garciaparra Boston
</span>x2 - average of 2000 Nomar Garciaparra Boston
x3 - average of <span>2001 Ichiro Suzuki Seattle 
</span>x4 - average of Manny Ramirez Boston  
x - average of <span>2003 Bill Mueller Boston 

</span><span>The sum of these five batting averages is 1.754:
x1 + x2 + x3 + x4 + x = 1.754

From the table:
x1 = 0.357
x2 = 0.372
x3 = 0.350
x4 = 0.349
x = ?

<u>0.357 + 0.372 + 0.350 + 0.349 + x = 1.754</u>

1.428 + x = 1.754
x = 1.754 - 1.428
<u>x = 0.326</u></span>
5 0
3 years ago
Plz help, asap, do not paste link for other website.
riadik2000 [5.3K]

Answer:

D is the answer not a or b or c

Step-by-step explanation:

none

3 0
3 years ago
Read 2 more answers
There are 3 people in Lee's family
kap26 [50]

Answer:

9

Step-by-step explanation:

the range is the difference between the lowest and the highest number on the series

here the range is 3 two members have size 6 different from 6 and 3 which range its 3

8 0
2 years ago
Question 3 &lt; &gt; In a particular class of 33 students, 18 are men. What fraction of the students in the class are women?​
Juli2301 [7.4K]

Answer:

Your answer is 15 Women

Step-by-step explanation:

33-18= 15

8 0
2 years ago
Identify the two pairs of complementary angles in the figure above. Justify your answer.
wolverine [178]

Answer:

1st pair of complementary angles: ∠c + ∠d

2nd pair of complementary angles: ∠g + ∠h

Step-by-step explanation:

the two solid lines are perpendicular, creating 4 right angles

1st pair of complementary angles: ∠c + ∠d

2nd pair of complementary angles: ∠g + ∠h

7 0
3 years ago
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