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4 years ago

5

The weight of an adult blue whale is 9 × 104 kilograms; the weight of an elephant is 3 × 103 kilograms. How many times heavier i

s the whale than the elephant?
30 kilograms
300 kilograms
3,000 kilograms
30,000 kilograms

1 answer:

kozerog [31]4 years ago

7 0

To determine how many times one variable to another variable, we get the ratio of both by dividing the values. For this case, we divide the weight of whale and the weight of the elephant.

9 × 10^4 kilograms / <span>3 × 10^3 kilograms = 30 <------ OPTION 1</span>

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Hey can you please help me posted picture of question

Flauer [41]

We can determine the correct graph by finding its roots

x² - 4x - 12 = 0

x² - 6x + 2x - 12 = 0

x(x-6) +2(x-6) = 0

(x+2)(x-6) = 0

This means the roots of the function are x=-2, and x=6 and the graph will cross x axis at these two points. From the given graphs, the graph B seems to cross these points.

So the answer to this question is option B

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3 years ago

The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statis

Ainat [17]

Answer:

The test statistic Z = 3.125

Step-by-step explanation:

<em>Given Population proportion P = 0.25</em>

<em>Given sample size 'n' = 696</em>

<em>Sample proportion 'p⁻' = 0.30</em>

Test statistic

$Z = \frac{p^{-} -P}{\sqrt{\frac{P Q}{n} } }$

$Z = \frac{0.30-0.25}{\sqrt{\frac{0.25 X 0.75}{696} } } = 3.125$

<u><em>Final answer</em></u>:-

The test statistic Z = 3.125

3 0

3 years ago

J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.

melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

P.Q. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean for mail-order sales = $74.50

$\bar X_2$ = sample mean for internet sales = $84.40

$s_1$ = sample standard deviation for mail-order purchases = $17.25

$s_2$ = sample standard deviation for internet purchases = $21.25

$n_1$ = sample of sales receipts for mail-order purchases = 16

$n_2$ = sample of sales receipts for internet purchases = 9

Also, $s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} }$ = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by ( $\mu_1-\mu_2$ ).

Now, 99% confidence interval for ( $\mu_1-\mu_2$ ) is given by;

= $(\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_) \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}$

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

= $(74.50-84.40) \pm (2.807 \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})$

= [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0

3 years ago

Which set of ordered pairs below is a function?

Paha777 [63]

The answer is A.

Ordered pairs that equate to a function would not have two separate points with the same x-value. In other words, every x-value must be associated with only one y-value.

5 0

3 years ago

Last month, Stephen neighbors paid him to take care of their fish when they went on vacation. HeHe spent $5 of his earnings on

Ira Lisetskai [31]

Answer:

Stephen's neighbors paid Stephen no more that $28.

Step-by-step explanation:

Given:

Stephen spent $5 of his earnings on snack.

He spent $17 in a new book.

He is left with no more than $6 left.

To describe how much Stephen's neighbors paid him.

Solution:

Let Stephen's earnings in dollars be = $x$

Amount left after spending on snacks in dollars = $x-5$

Amount left after spending on a new book in dollars = $x-5-17$ = $x-22$

The amount remaining is no more than $6.

Thus, the inequality representing the situation can be given as:

$x-22\leq6$

Solving for $x$

Adding 22 both sides.

$x-22+22\leq6+22$

$x\leq 28$

Thus, Stephen's neighbors paid Stephen no more that $28.

3 0

3 years ago