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3 years ago

13, 5, 4, 9, 7, 14, 4 The deviations are _____.

Mathematics

1 answer:

fenix001 [56]3 years ago

7 0

Answer:

B."5, -3, -4, 1, -1, 6, -4"

Step-by-step explanation:

We are given that

13,5,4,9,7,14,4

We have to find the deviation.

Mean= $\frac{sum\;of\;data}{total\;number\;of\;data}$

Using the formula

$Mean,\mu=\frac{13+5+4+9+7+14+4}{7}$

$Mean,\mu=\frac{56}{7}=8$

Deviation= $x_i-\mu$

$x_i-\mu$

13 5

5 -3

4 - 4

9 1

7 -1

14 6

4 - 4

Hence, option B is correct.

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What is the arc length of an angle of 2π 3 radians formed on the unit circle? A) π 3 B) 2π 3 C) 4π 3 D) 5π 3

mars1129 [50]

We know that
in a unit circle the radius is 1
therefore
[Length of a circumference]=2*pi*r------> 2*pi

if 2pi radians in a circle unit has a length of ------------> 2*pi
2pi/3 radians----------------------------> X
X=2pi/3

the answer is 2pi/3

5 0

3 years ago

Read 2 more answers

Can someone help me?

kirza4 [7]

Answer:

C. -36 3/10

Step-by-step explanation:

4 2/5 = 22/5

22/5 = 4.4

4.4(-8.25)

-36.3 = -36 3/10

Have a great day :3

8 0

3 years ago

What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

in this problem we have

the point $(5,12)$ is on the line of direct variation

Find the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

the equation is

$y=\frac{12}{5}x$

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

case A) point $(0,0)$

$x=0\ y=0$

Substitute the value of x and y in the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is true

therefore

the point $(0,0)$ is on the line of direct variation

case B) point $(2.5,6)$

$x=2.5\ y=6$

Substitute the value of x and y in the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is true

therefore

the point $(2.5,6)$ is on the line of direct variation

case C) point $(3,10)$

$x=3\ y=10$

Substitute the value of x and y in the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not true

therefore

the point $(3,10)$ is not on the line of direct variation

case D) point $(7.5,18)$

$x=7.5\ y=18$

Substitute the value of x and y in the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is true

therefore

the point $(7.5,18)$ is on the line of direct variation

case E) point $(12.5,24)$

$x=12.5\ y=24$

Substitute the value of x and y in the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not true

therefore

the point $(12.5,24)$ is not on the line of direct variation

case F) point $(15,36)$

$x=15\ y=36$

Substitute the value of x and y in the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is true

therefore

the point $(15,36)$ is on the line of direct variation

therefore

the answer is

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

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3 years ago

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AfilCa [17]

Answer:

Step-by-step explanatiion:

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Number less -2.7 are

-2.8; -2.9; -3.0; and so on

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3 years ago

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