For the arithmetic sequence
a₁, a₂, a₃, ...,
The n-th term is
![a_{n}=a_{1}+(n-1)d](https://tex.z-dn.net/?f=a_%7Bn%7D%3Da_%7B1%7D%2B%28n-1%29d)
where d = common difference.
Because a₁₀ = 41,
a₁ + 9d = 41 (1)
Because a₁₅ = 61
a₁ + 14d = 61 (2)
Subtract (1) from (2).
5d = 20
d = 4
From (1), obtain
a₁ = 41 - 9*4 = 5
Therefore
a₃ = 5 + 2*4 = 13
Answer: a₃ = 13
3,000.000 + 500.000 + 16.000 + 500 + 60 + 8 - Hope it helps!
The answer is
3 + (2) (4) - 4
answer is 7
(X,Y) 0=X and 0=Y if you plug in 0 for X and 0 for Y in Y=8X it will be 0=8(0). 8 times 0 is 0 which is the equation
45 games i just used a calculator will u please mark me brainiest hope this helps :)