The Answer To Your Question Is Organic Molecules
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Answer:
Hydroxide concentration of the sample is 1.3x10⁻⁶M
Explanation:
The equilibrium constant of water, Kw, is:
H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)
Kw is defined as:
Kw = 1.7x10⁻¹² = [H⁺] [OH⁻]
As the sample is of pure water, both H⁺ and OH⁻ ions have the same concentration because come from the same equilibrium, that is:
[H⁺] = [OH⁻]
We can write the Kw expression:
1.7x10⁻¹² = [OH⁻] [OH⁻]
1.7x10⁻¹² = [OH⁻]²
1.3x10⁻⁶M = [OH⁻]
<h3>Hydroxide concentration of the sample is 1.3x10⁻⁶M</h3>
Answer:
15.2 mL
Explanation:
First we calculate the volume of the copper
when this volume of copper is added to the water, the water level will rise by the level of the volume of copper. So the final volume is:
14.6 mL + 0.5580 mL = 15.158 mL
Since the measuring cylinder is graduated to one decimal place , we can round this up to 15.2 mL
Answer:
[CO₂] = 375 ppm
Explanation:
We can determine the concentration in value of ppm
ppm = mass of solute (mg) / mass of solution (kg)
Solution: atmosphere
Solute: CO₂
We convert the mass of CO₂ from g to mg → 0.1875 g . 1000 mg / 1g = 187.5 mg
We convert the mass of the atmosphere from g to kg: 500 g . 1 kg/1000g = 0.500 kg
ppm = 187.5 mg / 0.500kg = 375
