The answer is C. There are 6 Carbon (6x12.01=<span>72.06), 12 Hydrogen (12x1.01=12.12) and 6 Oxygen (6x16=96). Altogether 72.06,12.12 and 96 add to 180.18</span>

6 0

4 years ago

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If solid NaCl is added to a saturated water solution of PbCl2 at 20o C, a precipitate is formed. How would this affect the value

Vadim26 [7]

For the question above, the answer would be C. The Ksp remains the same. The common ion effect will change the concentrations of the ions in thesolution, but the value of Ksp is CONSTANT at a constant temperature thus Ksp does not change.

5 0

4 years ago

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- Calculate the Standard Enthalpy of the reaction below:

ANEK [815]

Answer:

Explanation:

We have the three equations:

$NH_{3(g)} + HCl_{(g)} => NH_4Cl_{(s)} ..... \Delta H = ? (1)\\2HCl_{(g)} => H_{2(g)} + Cl_{2(g)} .... \Delta H = +184.6 kJ (2)\\2H_{2(g)} + 1/2N_{2(g)} + 1/2Cl_{2(g)} => NH_4Cl_{(s)} ..... \Delta H = -314.2 kJ (3)\\ N_{2(g)} + 3H_{2(g)} => 2NH_{3(g)} .... \Delta H = +184.6kJ (4)$

(can you double check that it is 184.6kJ for both equations 2 and 4 because it seems unlikely). We need to solve for equation 1 by addition and changing equations 2, 3 and 4. After possibly some trial and error, we can find that if we flip equations 4, multiply equation 3 by 2, add the equations together, and then finally divide by 2, we can get equation 1. We will get the answer of -314.2 kJ. However, I am again skeptical about the delta H values for equation 2 and 4 so double check that. This method might be super confusing and it is really hard to explain. So what I would suggest you to watch videos on Hess' law.

3 0

3 years ago