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Fofino [41]
3 years ago
10

at a particular temperature, asample of pure water has a Kw of 1.7x10-12. what is the hydroxide concentration of this sample

Chemistry
1 answer:
Lena [83]3 years ago
6 0

Answer:

Hydroxide concentration of the sample is 1.3x10⁻⁶M

Explanation:

The equilibrium constant of water, Kw, is:

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Kw is defined as:

Kw = 1.7x10⁻¹² = [H⁺] [OH⁻]

As the sample is of pure water, both H⁺ and OH⁻ ions have the same concentration because come from the same equilibrium, that is:

[H⁺] = [OH⁻]

We can write the Kw expression:

1.7x10⁻¹² = [OH⁻] [OH⁻]

1.7x10⁻¹² = [OH⁻]²

1.3x10⁻⁶M = [OH⁻]

<h3>Hydroxide concentration of the sample is 1.3x10⁻⁶M</h3>
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Initial volume of gas V1 = 100L

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( 72°C + 273= 345K)

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According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

100L/408K = V2/345K

To get the value of V2, cross multiply

100L x 345K = V2 x 408K

34500 = V2 x 408K

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V2 = 84.56L

Thus, the volume of the gas becomes 84.56 liters

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What is the mass of six of these marbles? What is the volume? What is the<br> density?
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Answer:

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Answer:

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In the net ionic equation we include only the ions that participate in the reaction and the molecular species.

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