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schepotkina [342]
3 years ago
10

Make a suggestion on how you will deal with the problem..

Chemistry
2 answers:
photoshop1234 [79]3 years ago
8 0

Answer:

If you are asking to suggest a method to preserve the extinction of this species of pigeon then

1. Governments should derive a law that will prevent hunting of these pigeons.

2. These pigeons should be given a place in sanctuaries with hospitable habitat made available.

3. If someone sees a bird of this kind care should be taken not to harm it intentionally or accidentally.

4. Breeding this type of Birds should be Promoted to increase their number

Trava [24]3 years ago
7 0

Answer:

and the last name then select a City the solution if they are getting elimination method if I can tell u that is telling you about me to this email and delete this email and any attachments may contain confidential information and rupees hundred years ago the pair in the solution if I can tell you my story of my teacher not respond please ask me to this email and any attachments is intended only for the independence of Bangladesh and what is the correct answer is yes we have to come at your earliest convenience and what is the correct answer

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How many significant figures in 11 soccer players
maria [59]
Counting gives an exact number and exact numbers have infinite sig figs.
3 0
3 years ago
Which two layers are part of the thermosphere?
borishaifa [10]

Answer:

exosphere and ionosphere.

Explanation:

very high up,the earth's atmosphere becomes very thin. the region where atoms and moleculesescape into space is referred to as the exosphere. exosphere is on top of the thermosphere.

scientists what is called the ionospherean extension of the thermosphere. so technically, ionosphere is not another atmospheric layer.

6 0
3 years ago
Read 2 more answers
33.56 g of fructose (C6H,206) and 18.88 g of water are mixed to obtain a 40.00 ml solution a. What is this solution's density? b
Darina [25.2K]

Explanation:

Mass of fructose = 33.56 g

Mass of water =  18.88  g

Total mass of the solution =  Mass of fructose + Mass of water = M

M = 33.56 g + 18.88  g =52.44 g

Volume of the solution = V = 40.00 mL

Density =\frac{Mass}{Volume}

a) Density of the solution:

\frac{M}{V}=\frac{52.44 g}{40.00 mL}=1.311 g/mL

b) Molar mass of fructose = 180.16 g/mol

Moles of fructose = n_1=\frac{ 33.56 g}{180.16 g/mol}=0.1863 mol

Molar mass of water = 18.02 g/mol

Moles of water= n_2=\frac{ 18.88 g}{18.02 g/mol}=1.0477 mol

Mole fraction of fructose in this solution:\chi_1

\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1863 mol}{0.1863 mol+1.0477 mol}

\chi_1=0.1510

Mole fraction of water = \chi_2=1-\chi_1=0.8490

c) Average molar mass of of the solution:

=\chi_1\times 180.16 g/mol+\chi_2\times 18.02 g/mol

=0.1510\times 180.16 g/mol+0.8490\times 18.02 g/mol=42.50 g/mol

d) Mass of 1 mole of solution = 42.50 g/mol

Density of the solution = 1.311 g/mL

d) Specific molar volume of the solution:

\frac{\text{Average molar mass}}{\text{Density of the mass}}

=\frac{42.50 g/mol}{1.311 g/mL}=32.42 mL/mol

5 0
3 years ago
Can I have some help please on #2,4,5
zzz [600]
It differs because a steam turbine runs off of a magnetic field and a steam engine runs off of coal 

hope this helps :)




5 0
3 years ago
A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl
diamong [38]

Answer:

\large \boxed{\text{98 m$\cdot$s}^{-2}}

Explanation:

The formula for the velocity of the ball is

v = \sqrt{2gh}

1. Velocity at time of impact

v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}

3. Acceleration

a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}

5 0
3 years ago
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