Solve (x+5)+4=16 by first subtracting 4 and then 5. Show your work and justify each step.

Mathematics

1 answer:

Vinil7 [7]2 years ago

3 0

$(x+5)+4=16\ \ \ subtract\ 4 \ and \ 5 \ to\ both\ sides \\\\x+5+4-5-4=16-4-5 \\\\x=7$

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The following statement is either true (in all cases) or false (for at least one example). If false, construct a specific e

matrenka [14]

Answer:

False, counterexample below

Step-by-step explanation:

Denote the unit vectors of R^3 by $e_1=(1,0,0), e_2=(0,1,0), e_3=(0,0,1)$ . Now consider $v_1=e_1, v_2=2e_1$ and $v_3=e_3$ . We have that $v_1, v_2,v_3 \in \mathbb{R}^3$ . Also, the vector $v_3$ is not a linear combination of $v_1, v_2$ because any linear combination of these two vectors will have third coordinate zero, but v_3 has third coordinate 1 so they can't be equal.

However, the set $\{v_1, v_2,v_3\}$ is not linearly independent, because $2v_1-v_2+0v_3=0$ is a non-trivial linear combination of these vectors that equals zero.