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3 years ago

Solving the right triangle (round to the nearest tenth)

Mathematics

2 answers:

den301095 [7]3 years ago

7 0

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for B

B = 180° - (90 + 43)° = 180° - 133° = 47°

--------------------------------------------------------------

tan43° = $\frac{opposite}{adjacent}$ = $\frac{23}{b}$

Multiply both sides by b

b × tan43° = 23 ( divide both sides by tan43° )

b = $\frac{23}{tan43}$ ≈ 24.7 ( to the nearest tenth )

-----------------------------------------------------------------

sin43° = $\frac{opposite}{hypotenuse}$ = $\frac{23}{c}$

Multiply both sides by c

c × sin43° = 23 ( divide both sides by sin43° )

c = $\frac{23}{sin43}$ ≈ 33.7 ( to the nearest tenth )

djyliett [7]3 years ago

3 0

Answer:

idk

Step-by-step explanation:

idk sorry wish i could help u

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