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insens350 [35]
3 years ago
5

the area of triangle b is 64 times greater than the area of triangle a.the perimeter of triangle b is how many times greater tha

n the perimeter of triangle a?

Mathematics
1 answer:
aev [14]3 years ago
8 0
So yah.. perimeter of triangle b is
= 32 + a/2

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In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
snow_lady [41]

If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB

Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°

Next, look at ΔADB.  ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°

Now look at ΔADC.  Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>

Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.

CD = 4 cm (given) so AC = 2(4 cm) = 8 cm

Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 <em>by segment addition postulate.</em>

Lastly, look at ΔBHD.  Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.

BD = 12 cm, so HD = \frac{12}{2}cm = 6 cm

Answer: 6 cm



8 0
3 years ago
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How fast did the plane descend?
ohaa [14]

Answer:

5 meters per second

Step-by-step explanation:

First you must find the slope of the graph. Take the rise/run of the function. The graph starts at 8500 meters and goes down to 7500 meters in 200 seconds. the difference between the change in meters is 1000 meters and the change in seconds is 200 seconds. That is 1000/200. This can be simplified to 5/1 which is 5 meters per second.

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3 years ago
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Since 16 and 25 are perfect squares you can factor the first part.
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Which can be expanded if necessary,
= -209+150b-25b^2
4 0
3 years ago
Let f(y) = y^4 - 3y^3 + y - 3 and g(y) = y^3 + 7y^2 - 2. Find f(y) + g(y). Write your answer as a polynomial with terms of decre
Anarel [89]
<h3>Answer:   y^4 - 2y^3 + 7y^2 + y - 5</h3>

Work Shown:

h(y) = f(y) + g(y)

h(y) = (y^4 - 3y^3 + y - 3) + (y^3 + 7y^2 - 2)  

h(y) = y^4 - 3y^3 + y - 3 + y^3 + 7y^2 - 2  

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h(y) = y^4 - 2y^3 + 7y^2 + y - 5

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True or false, A function is a relation if and only if the x-values do not repeat in a given set
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Its false because it can't repeat in a set.
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