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Flura [38]
3 years ago
7

Jayla had 4 chocolate chip cookies and 3 sugar cookies. Her sister ate two of her chocolate chip cookies. What fraction of cooki

es does she have left?
Mathematics
1 answer:
Ahat [919]3 years ago
4 0
The starting fraction is 7/7
now you subtract 2 for the 2 cookies eaten
7/7 - 2/7 = 5/7
your end fraction is 5/7 
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Combine like radicals to get your answer. <br><br> image attached
spin [16.1K]

Answer:

So the final answer is

-8\sqrt{3}

Step-by-step explanation:

Radicals:

In mathematics, a radical expression is defined as any expression containing a radical (√) symbol. Many people mistakenly call this a 'square root' symbol, and many times it is used to determine the square root of a number. However, it can also be used to describe a cube root, a fourth root, or higher.

The given expression is

-5\sqrt{3} -3\sqrt{3}

Now take common radical out so we will get

\sqrt{3}(-5-3)

Now add the Parenthesis part.

\sqrt{3}(-8)

So the final answer is

-8\sqrt{3}

5 0
3 years ago
How would I solve for the area of this triangle? Please help
Lyrx [107]
You would solve it by multiplying the sides of the triangle
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2 years ago
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complete the steps to find the quotient of 492 ÷ 6. enter your answer in the space.step 1( ___÷6) +(180÷ 6)+( ____÷ 6) step 2 __
uranmaximum [27]
I'll go thru the problem and then you fill in the blanks yourself.
          
            8   2
    ________
6 /   4   9   2
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8 0
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The line passes through point (3 - 4) and (-2 2)​
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2 years ago
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A pilot was scheduled to depart at 4:00 pm, but due to air traffic, her departure has been delayed by 15 minutes. Air traffic co
Sladkaya [172]

Answer:

y = (1/2)x + 15

Step-by-step explanation:

First, we need to identify the parts of the problem that we already know:

1) The pilot was originally scheduled to depart at 1600 (4:00 pm).

2) The pilot's departure was delayed by 15 minutes.

3) the traffic control approved a new flight plan that would allow the pilot to travel to her destination two times faster than her original flight plan.

For the problem's sake, let us pretend that the pilot's original flight plan was going to take two hours. Had he/she left at 4:00 pm, the pilot would have landed at 6:00 pm.

With a delay of 15 minutes, the duration of the flight would still remain constant, so the pilot would arrive at their destination two hours later, at 6:15 pm.

With the new flight plan, the pilot's travel time would be cut in half, so it would be 1/2 of x (time, in minutes, of original flight). Thus, her new flight time would only be one hour (60 minutes).

So, now we have to subtract 1/2 from the original flight time, as well as adding the 15 minute delay for departure. Now we can create a formula:

y = (1/2)x + 15

Y equals the total amount of time (in minutes) that it would take for the plane to leave. We divide x (total time of original flight) by 2, because her new flight plan will be twice as fast. Then we have to take into account the extra 15 minute delay!  

8 0
3 years ago
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