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Flura [38]
3 years ago
7

Jayla had 4 chocolate chip cookies and 3 sugar cookies. Her sister ate two of her chocolate chip cookies. What fraction of cooki

es does she have left?
Mathematics
1 answer:
Ahat [919]3 years ago
4 0
The starting fraction is 7/7
now you subtract 2 for the 2 cookies eaten
7/7 - 2/7 = 5/7
your end fraction is 5/7 
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Plzz help me with thsi quistion
Salsk061 [2.6K]

Answer:

98 ft

Step-by-step explanation:

14x7

=98 ft

8 0
2 years ago
Read 2 more answers
See the attachment below for the question.
tangare [24]

Answer:

The correct answer is third option

x = 3

Step-by-step explanation:

It is given that,

4ˣ = 8⁽ˣ ⁻ ¹⁾

<u>To find the value of x</u>

4ˣ  = (2²)ˣ

8⁽ˣ ⁻ ¹⁾ = (2³)⁽ˣ ⁻ ¹⁾

4ˣ = 8⁽ˣ ⁻ ¹⁾

(2²)ˣ =  (2³)⁽ˣ ⁻ ¹⁾

2²ˣ = 2⁽³ˣ ⁻ ³⁾

2x = 3x - 3

3x - 2x = 3

x = 3

The correct answer is third option

x = 3

5 0
3 years ago
Read 2 more answers
Please help. Marika is training for a race.
Anika [276]

Let's call n the number of days Marika's been training for the race, and a_n the distance she runs on the nth day in meters. After the first day, when n = 1, she runs 100 meters, so


a_1=100


On the second day, she runs an additional 4 meters, on the third day, another 4, and so on. Here's what that looks like mathematically:


a_2=100 + 4\\a_3=100 + 4 + 4\\a_4=100+4+4+4


It would be easier to write this continued addition as multiplication, in which case those same equations would look like


a_2 = 100 + 4(1)\\a_3 = 100 + 4(2)\\a_4=100+4(3)


Notice that, in every case, the number 4 is being multiplied by is 1 less than n. We could even write for our first term that a_1=100+4(0). In general, we can say that


a_n=100+4(n-1)


Which is expressed by option B.


(Bonus: What piece of information from this question did we not need to use here?)

3 0
3 years ago
What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9
weeeeeb [17]

The difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}

Take LCM

\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0
2 years ago
A gym membership<br> charges an initial fee<br> of $150 then $20 per<br> month.
Vsevolod [243]

Answer:

n=150+20m

Step-by-step explanation:

we don't know how many months they're charging for, so we don't know the total of the amount.

7 0
3 years ago
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