There is so much controversy about this question on the internet (well not this question exactly but the idea of taking a reciprocal of a discontinuous function).
Some say you can if you make it clear that the point causing the trouble is excluded in some way. Others say that you cannot contemplate the idea. You are creating a meaningless situation with no definition. It really depends on what you have been told about division by 0. There are ways of getting around this, but you are not taking a calculus course and therefore you likely don't have the tools to deal with it. In any event, it does not look to me like you know about limits yet.
Your marker or teacher or tutor can go either way on this problem and be justified in marking you wrong no matter what you do. As instructed I will put what I think should be done in the comment section. And remember, I'm counting noses and going with the majority when I answer this. It's not anything I'm 100% certain of, but neither is anyone else.
Answer:
you need to attach graphs so we can see & help lol ; ]
Step-by-step explanation:
For this case we have the following expression:
From here, we must clear the value of a.
We then have the following steps:
Place the terms that depend on a on the same side of the equation:
Do common factor "a":
Clear the value of "a" by dividing the factor within the parenthesis:
Answer:
The clear expression for "a" is given by:
The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.
This means that Purple #1 is <u>a redder</u> shade of purple than Purple #2.
Purple #2 is <u>a bluer</u> shade of purple than Purple #1.
Step-by-step explanation:
The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.
Making blue's quantity as 3 parts for purple #1 implies red part becomes 1.5 to maintain the ratio 1:2
Purple #1 has 1/3 parts red and 2/3 parts blue. Purple #2 has 1/4th part red and 3/4th part blue.
Hence, Purple #1 is <u>a redder</u> shade of purple than Purple #2.
From the above explanation, <u>Purple #2</u> is a bluer shade of purple than Purple #1.
<em>Sure hopes this helps you :)</em>
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