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lord [1]
3 years ago
11

What is the solution of the following system?

Mathematics
1 answer:
erica [24]3 years ago
8 0

Answer:

The answer to your question is: both lines are the same.

Step-by-step explanation:

                                   

                                             3x + 3y = 10

                                            -9x -9y = -30

Elimination method

                                            9x + 9x = 30

                                           -9x -  9y = -30

                                              0     0      0

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A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4
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Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

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Step-by-step explanation:

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We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

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Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

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= By using the Scientific calculator notation;

distance = 106.109 m

4 0
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