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Tom [10]
2 years ago
7

Select the expression that can be used to find the price of a $350 telescope after a 48% markup.

Mathematics
1 answer:
zvonat [6]2 years ago
4 0

Answer:

c

Step-by-step explanation:

you have to turn the48 to a decimal

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27.96 round to the nearest tenth
Serjik [45]
Your tenths place is the 6. If a number is above 5, you round up. and since this number is 96, you would round to 100, but since its a decimal, you round up the actual number to make 28.00. Final answer: 28
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3 years ago
What is the number 21.0384 rounded to the nearest hundredth?
Anton [14]

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21.04

Step-by-step explanation:

the 8 is closest to 10 so that would make the 3 a 4.

3 0
2 years ago
You tape two pieces of paper together that each measure
sertanlavr [38]

Answer:

The paper is 60.73 cm long.

Step-by-step explanation:

The two pieces of paper each measure 41.36 cm, so those together would be 82.72 cm. Subtracting the 21.99 that is cut off, you're left with 60.73 cm. Hope this helped!

8 0
3 years ago
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Can someone please answer this question please help please answer it correctly and please show work please help I need it please
mr_godi [17]

Answer:

Step-by-step explanation:

24)

200= 3(21) + 4x

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.5(pi)= about 1.6

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3 0
3 years ago
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How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
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