8x-6y=-96 add to this -4 times the second equation...
-8x-12y=-48
___________
-18y=-144
y=8, this makes 8x-6y=-96 become:
8x-48=-96
8x=-48
x=-6
so the solution to the system of equations is the point:
(-6,8)
Subtract 6.75 from 15.2 to find what he did on Sunday, because supposed the number of miles he ran on Sunday was x. Therefore, the formula should be x + 6.75 = 15.2
Solve that, and you should get that Jim ran 8.45 miles on Sunday.
Answer:
1. Complex number.
2. Imaginary part of a complex number.
3. Real part of a complex number.
4. i
5. Multiplicative inverse.
6. Imaginary number.
7. Complex conjugate.
Step-by-step explanation:
1. <u><em>Complex number:</em></u> is the sum of a real number and an imaginary number: a + bi, where a is a real number and b is the imaginary part.
2. <u><em>Imaginary part of a complex number</em></u>: the part of a complex that is multiplied by i; so, the imaginary part of the complex number a + bi is b; the imaginary part of a complex number is a real number.
3. <em><u>Real part of a complex number</u></em>: the part of a complex that is not multiplied by i. So, the real part of the complex number a + bi is a; the real part of a complex number is a real number.
4. <u><em>i:</em></u> a number defined with the property that 12 = -1.
5. <em><u>Multiplicative inverse</u></em>: the inverse of a complex number a + bi is a complex number c + di such that the product of these two numbers equals 1.
6. <em><u>Imaginary number</u></em>: any nonzero multiple of i; this is the same as the square root of any negative real number.
7. <em><u>Complex conjugate</u></em>: the conjugate of a complex number has the opposite imaginary part. So, the conjugate of a + bi is a - bi. Likewise, the conjugate of a - bi is a + bi. So, complex conjugates always occur in pairs.
Answer:
(-4.5, 2.5)
Step-by-step explanation:
The solution for two graphed linear equations is the intersection (The point where two lines meet or cross).
Hi! Basically, the problem is asking us to find the values of a, b, and c in the equation

. Since we have three unknowns, we just need three equations. We can find these equations by using the data in the table.
First let's plug x = 0 and f(x) = 0.


Now that we know c, it's time to pick two more pairs. Let's plug-in (2,78) and (4,152)


Before proceeding with the process of eliminating one variable, let us first reduce both equations to their lowest terms. We divide the first equation by 2 and we divide the second one by 4.


Next, we subtract equation 2 from equation 1.


Finally, we substitute the value of a to equation 2 to get the value of b.


Therefore, the function should be