I did the problem and I got negative 4 over 9
24x^2 +25x - 47 53
----------------------- = -8x -3 - ---------------
ax-2 ax-2
add 53/ax-2 to each side
24x^2 +25x - 47+53
----------------------- = -8x -3
ax-2
24x^2 +25x +6
----------------------- = -8x -3
ax-2
multiply each side by ax-2
24x^2 +25x +6 = (ax-2) (-8x-3)
multiply out the right hand side
24x^2 +25x +6 = -8ax^2 +16x-3ax +6
24 = -8a 25 = 16 -3a
a = -3 9 = -3a
a = -3
Choice B
X= 4/7 because it would be
4/35x=16/245
which would be 28x=16
simplified it would be 4/7
Answer:
A) 48 in : initial height of the water
B) 40.5 in : height of the water after 5 days
C) 32 days
D) Yes, should be restricted.
Domain: 0 ≤ d ≤ 32
Step-by-step explanation:
A)
48 in is the initial height of the water
B)
40.5 in is the height of the water after 5 days
C) when the pool is empty, h = 0.
So set the equation to zero and solve for d.
D) Yes, the domain should be restricted because when d > 32, h < 0 and the height of the water in the pool cannot be negative
Domain: 0 ≤ d ≤ 32
The expression (n+3) represents the measure of an exterior angle of a regular octadecagonal.