5x 2 +1=−13x−5 the two is an exponent for the 5x.
2 answers:
Answer:
x = - 2, x = -
Step-by-step explanation:
Given
5x² + 1 = - 13x - 5 ( add 13x - 5 to both sides )
5x² + 13x + 6 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 5 × 6 = 30 and sum = 13
The factors are 10 and 3
Use these factors to split the x- term
5x² + 10x + 3x + 6 = 0 ( factor the first/second and third/fourth terms )
5x(x + 2) + 3(x + 2) = 0 ← factor out (x + 2) from each term
(x + 2)(5x + 3) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
5x + 3 = 0 ⇒ 5x = - 3 ⇒ x = -
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This is what I got when i graphed it.
Answer:
u as the subject of the given formula is,
Step-by-step explanation:
Given;
v² = u²+2as
To make u the subject of the formula, the following steps are taken;
v² = u²+2as
v² - 2as = u²
take the square - root of both sides of the equation;
Thus, u as the subject of the given formula is,