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- zinc [Zn] + copper sulfate [Cu(SO4<span>)
</span>Balanced equation:Zn + Cu(SO4) → Zn(SO4<span>) + Cu
- </span>aluminum [Al] + copper sulfate[Cu(SO4)]Balanced equation:2Al + 3Cu(SO4) → Al2(SO4)3<span>+ 3Cu
- </span>zinc [Zn] + silver nitrate [Ag(NO3)]Balanced equation:Zn + 2Ag(NO3) → 2Ag + Zn(NO3)<span>2
- </span>copper [Cu] + silver nitrate [Ag(NO3)]
Balanced equation:Cu + Ag(NO3) → Cu(NO3<span>) + Ag</span>
This is because U-235 decays naturally by a process known as alpha radiation. This means that it releases an alpha particle (two neutrons and two protons connected together).
Another reason that U-235 is ideal for producing nuclear power is that unlike most materials, U-235 can undergo induced fission. When a free neutron collides with a U-235 nucleus, the nucleus will usually capture the neutron and split extremely quickly. The splitting of a single U-235 atom can release roughly 200 MeV (million electron volts).
Answer:
The nucleus of an atom consists of Protons and Neutrons.-A.
Given:
Mixture of vitamin water = 75% pure water & 25% concentrated vitamin drink.
To find:
Quantity of water to be added to 16 gallons of concentrated vitamin drink to prepare a tank of vitamin water.
Solution:
Let total amount of mixture be x.
25% of x = 16 gallons (from given information)
When 25% of x is 16 gallons, the remaining 75% of x will be calculated as below:
(16/25)*75 = 48
Answer: 75% of x = 48 gallons. This means 48 gallons pure water is required to be added to mixture to prepare a tank of vitamin water.
Answer:
The change in temperature that occurs when 8000 J of heat is used by a mass 75 g of water is 25.4 °C
Explanation:
H = mc ΔT
m = 75 g
c = 4. 200 J/ g °C
H = 8000 J
ΔT =?
Rearranging the formula, making ΔT the subject of formula;
ΔT = H / m c
ΔT = 8000 / 75 * 4.200
ΔT = 8000 / 315
ΔT = 25.4 °C
