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Solnce55 [7]
3 years ago
7

In the formation of a solution how does the solvent differ from the solute

Chemistry
1 answer:
dlinn [17]3 years ago
6 0
Solute is a substance that dissolves in a solvent in order to form a solution. Solutes can be in liquid, gaseous or solid phase. Normally, in a solution, solutes are in a lesser amount than the solvents. When a solution has the maximum amount of solutes it can dissolve, then the solution is said to be saturated.
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Write the formulas of the following compounds:
ddd [48]

Answer:

a) Chloride dioxide  

     ClO_2

b) Di nitrogen tetra oxide

   N_2O_4

c) Potassium phosphide

   H_2K_3P^{+2}

d) Silver -Ag

e) Aluminium nitride - AlN

f) Silicon dioxide

 SiO_2

I) Sulfide

S^{2-}

5 0
3 years ago
How many joules of energy are absorbed when 36.2 grams of water is evaporated?
AfilCa [17]

Answer:

.........................................................

Explanation:

8 0
3 years ago
Use standard enthalpies of formation to calculate Δ H ∘ rxn for each reaction. MISSED THIS? Read Section 7.9; Watch KCV 7.9, IWE
Eva8 [605]

Answer:

Standard Heat of Reaction 1 = -136.2 kJ/mol

Standard Heat of Reaction 2 = -41.166 kJ/mol

Standard Heat of Reaction 3 = -136.07 kJ/mol

Standard Heat of Reaction 4 = 279.448kJ/mol

Explanation:

C₂H₄ (g) + H₂ (g) → C₂H₆ (g)

CO (g) + H₂O (g) → H₂ (g) + CO₂ (g)

3NO₂ (g) + H₂O (l) → 2HNO₃ (aq) + NO (g)

Cr₂O₃ (s) + 3CO (g) → 2Cr (s) + 3CO₂ (g)

The required standard heat of formation for each of the reactants and product above, as obtained from literature is listed below.

C₂H₄ (g), 52.5 kJ/mol

H₂ (g), 0 kJ/mol

C₂H₆ (g), -83.7 kJ/mol

CO (g), -110.525 kJ/mol

H₂O (g), -241.818 kJ/mol

H₂ (g), 0 kJ/mol

CO₂ (g), -393.509 kJ/mol

NO₂ (g), 33.2 kJ/mol

H₂O (l), -285.8 kJ/mol

HNO₃ (aq), -206.28 kJ/mol

NO (g), 90.29 kJ/mol

Cr₂O₃ (s), -1128.4 kJ/mol

CO (g), -110.525 kJ/mol

Cr (s), 0 kJ/mol

CO₂ (g), -393.509 kJ/mol

Note that

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

C₂H₄ (g) + H₂ (g) → C₂H₆ (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (1×-83.7) = -83.7 kJ/mol

ΔH∘(reactants) = (1×52.5) + (1×0) = 52.5 kJ/mol

ΔH∘(rxn) = -83.7 - 52.5 = -136.2 kJ/mol

CO (g) + H₂O (g) → H₂ (g) + CO₂ (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (1×0) + (1×-393.509) = -393.509 kJ/mol

ΔH∘(reactants) = (1×-110.525) + (1×-241.818) = -352.343 kJ/mol

ΔH∘(rxn) = -393.509 - (-352.343) = -41.166 kJ/mol

3NO₂ (g) + H₂O (l) → 2HNO₃ (aq) + NO (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (2×-206.28) + (1×90.29) = -322.27 kJ/mol

ΔH∘(reactants) = (3×33.2) + (1×-285.8) = -186.2 kJ/mol

ΔH∘(rxn) = -322.27 - (-186.2) = -136.07 kJ/mol

Cr₂O₃ (s) + 3CO (g) → 2Cr (s) + 3CO₂ (g)

ΔH∘(rxn) = ΔH∘(products) - ΔH∘(reactants)

ΔH∘(products) = (2×0) + (3×-393.509) = -1,180.527 kJ/mol

ΔH∘(reactants) = (1×-1128.4) + (3×-110.525) = -1,459.975 kJ/mol

ΔH∘(rxn) = -1,180.527 - (-1,459.975) = 279.448 kJ/mol

Hope this Helps!!!

4 0
3 years ago
The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in
olya-2409 [2.1K]

Answer:

2: Moved faster and spread farther apart.

Explanation:

Restate the question: The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in the liquid.

1. moved slower and closer together.

2.moved faster and spread farther apart.

3. contracted in size when heated.

4. expanded in size when heated.

Water that is cold does not have the energy to bounce of the walls, instead it is like a group of animals they group together for the warmth of the others when it gets really cold.

So it cant be 1.

We all know that power lines sag lower on a hot day (or a tire for a car, it has increases pressure). but those are different types of molecules.

So that rules out 3 and 4.

Which leaves you with 2.

The increase in temperature causes the water molecule to gain energy and move quickly, which resulted in water molecule that are farther apart and an increase in water volume.

Hope it helps!

7 0
2 years ago
Read 2 more answers
Why didn't you just clean the spill with water?
Allisa [31]

Answer:

if you did it would probably make it bigger...

Explanation:

:)

3 0
3 years ago
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