Answer:
1.) 13 g C₄H₁₀
2.) 41 g CO₂
Explanation:
To find the mass of propane (C₄H₁₀) and carbon dioxide (CO₂), you need to (1) convert mass O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles C₄H₁₀/CO₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles C₄H₁₀/CO₂ to mass C₄H₁₀/CO₂ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answers should have 2 sig figs to match the sig figs of the given value.
Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)
Molar Mass (C₄H₁₀): 58.124 g/mol
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O
48 g O₂ 1 mole 2 moles C₄H₁₀ 58.124 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 13 g C₄H₁₀
48 g O₂ 1 mole 8 moles CO₂ 44.007 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 41 g CO₂
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Molarity of the resulting solution will be 1.33 M.
<u>Explanation:</u>
First we have to find the number of moles for each of the solution using the formula, moles = molarity × volume
For cup 1 = 1 M ×0.05 L = 0.05 moles
For cup 2 = 2.5 M × 0.05 L= 0.125 moles
For cup 3 = 0.5 M × 0.05 L = 0.025 moles
Total moles = 0.05 + 0.125 + 0.025 = 0.2 moles
We have to find the total volume as, 0.05 + 0.05 + 0.05 = 0.15 L
Now we have to find the molarity as, moles / volume = 0.2 moles/ 0.15 L = 1.33 M
Answer:
OPTION B
Explanation:
Nuclear "fission" is the breakdown of the nucleus of a radioactive element into two or more nuclei accompanied by the release of energy. I guess that pretty much explains it.
Answer:
the bike is moving at a speed of 0.115810 mph
