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tresset_1 [31]
3 years ago
13

This is due Monday but I want to get it done today, because the teacher is still going to check it, and I have practicly nothing

answered.
Mathematics
1 answer:
Crank3 years ago
7 0
You don’t have anything attached:(
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A line with a slope of 3 passes through the point (2, 5). Write an equation for this line in point-slope form.
Phantasy [73]

Answer:

slope = 3

point (2, 5)

b = y - m*x

b = 5 -3*2

b = -1

Then we enter the slope and the value of b into this equation:

y = mx + b

y = 3x -1

Source: https://www.1728.org/distance.htm

Step-by-step explanation:

3 0
3 years ago
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Line / goes through the Point 1-N-1) and is perpendicular to the line through (-6,5) and (-3,-2)
rosijanka [135]

Answer:

by using kinetic and potentail energy

7 0
3 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is P(X=0) \approx 0.8659

The probability of at least 1 failure in a 24-hour day is P(X\geq 1 )\approx 0.3508

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

P(X)=\frac{e^{-\mu}\mu^x}{x!}

Let X be the number of failures of a testing instrument.

We know that the mean \mu = 0.018 failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is \mu=8\cdot 0.018=0.144

P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is \mu=24\cdot 0.018=0.432

P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508

3 0
3 years ago
A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As
Semenov [28]

Answer:

0.2564\text{ pounds}

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the X percentile for the television weights, use the formula:

X=\mu +k\sigma, where \mu is the average of the set, k is some constant relevant to the percentile you're finding, and \sigma is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute \mu=5, k=1.282, and \sigma=0.1:

X=5+(1.282)(0.1)=5.1282

Therefore, the 90th percentile weight is 5.1282 pounds.

Repeat the process for calculating the 10th percentile weight:

X=5+(-1.282)(0.1)=4.8718

The difference between these two weights is 5.1282-4.8718=\boxed{0.2564\text{ pounds}}.

8 0
3 years ago
Read 2 more answers
Hi! how many times does 9 go into 67???? plz help me
Nina [5.8K]

Answer:

it goes into 67 7 times

Step-by-step explanation:


8 0
3 years ago
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