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2 years ago

Help :( explain the meaning of -500 in context to the problem,

Mathematics

2 answers:

Nadya [2.5K]2 years ago

6 0

The equation of the distance of the plane from the city in Ecuador is a

linear equation that has a constant rate of change.

The -500 is the rate at which the distance of the plane from Ecuador changes every hour.

Reasons:

The equation that estimates the distance of the plane from the city in

Ecuador is d = 2565 - 500·t

Where;

d = The distance in miles from the city in Ecuador

t = The time in hours after taking off from the city in Pennsylvania

Required:

The meaning of -500 in the context of the problem.

Solution:

By using dimensional analysis, we have;

Given that d is in miles and t is in hours, 2,565 is in miles, and 500 × t is in

miles.

Therefore, -500 is in miles per hour, which is the speed of the plane.

The -500 therefore, in the context, is the number of miles, the rate, by

which the plane becomes closer to the city in Ecuador every hour.

Learn more rate of change here:

brainly.com/question/1388646

LuckyWell [14K]2 years ago

3 0

We can analice through a dimensional evaluation, every term in any equation.

Solution is:

The term - 500 × t

represents, the quantity of miles travel in the time t

Looking carefully each term in the equation:

d = 2565 - 500×t

And knowing:

d, is distance in miles
t, is time in hours
The fact that, adding and subtracting are mathematical operations with homologous quantities. By homologous quantities we must understand that we add and subtract apples plus or (minus) apples. We never add pencils plus boxes

We are able to answer the question.

Then in the expression

d = 2565 - 500×t

As d is in miles, we must understand that 2565 is the total distance of the trip, also in miles, should and the product -500×t must also be in miles. According to that, the number 500 is necessarily in miles/hours (the speed of the plane), and the negative sign for 500 means that the total distance 2565 miles should be subtracted from the total time of travel.

For instance if t = 1 hour

d = 2565 miles - 500 (miles)/hour × 1 (hour)

As we can see we are able to determine the total time of fly, as the total distance between the cities is 2565, and 500 is the speed of the plane (constant during the whole trip).

For the whole trip

d = 2565 miles then total fly time is:

2565 (miles)/ 500 (miles/hour)×t

To get . t = 5.13 h

Related link:brainly.com/question/8956323

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Answer:

2 pair shorts and for t-shirts and sandals possible cases are

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Step-by-step explanation:

Total money spent by Heidi on the clothing items is $60.

Now , she bought 2 pairs of short for $10 each , so, the money spent on shorts will be $20.

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3 years ago

Solve for s. 5/9s+13/9s=24

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Solving for s, I get s = 12.

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3 years ago

Read 2 more answers

Find the 23rd term of this sequence -25,-15,-5,5....

notsponge [240]

Answer:

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Step-by-step explanation:

To find the 23rd term of this sequence, we can use the arithmetic sequence formula $a_{n} =a_{1} +(n-1)d$ where,

$a_{n}$ = $n^{th}$ term

$a_{1}$ = first term

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3 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

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Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

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