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3 years ago

Help please!!!!!!!!!

Mathematics

1 answer:

SOVA2 [1]3 years ago

6 0

Find the area of the triangles and smal ler square and add them together ; and find the area of the complete square and set them equal to each other (these are known truths)
triangle: l×w /2
square: s^2
There are 4 triangles so

4 (1/2ab)+c^2= (a+b)(a+b)
simplify

2ab+c^2= a^2+2ab+b^2
-2ab both sides

c^2=a^2+b^2

tada!! it's proven :)

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Write the equition of the line that passes through the pair of points (8,-8) and (9,-4)

ANTONII [103]

Answer: More Info

Step-by-step explanation:

8 0

3 years ago

The heaviest dinosaur is estimated to have welghed 2.8 x 10^5 pounds. The average car weighs about 4 x 10^3 pounds.

34kurt

Answer:

Step-by-step explanation:

Apparently, you want the ratio of the weights:

(dino weight)/(car weight) = (2.8×10^5)/(4×10^3)

= (2.8/4)×10^(5-3) = 0.7×10^2 = 0.7×100

= 70

The heaviest dinosaur weighed about 70 times the weight of an average car.

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Your calculator can do arithmetic in scientific notation. So can any spreadsheet.

The applicable rule of exponents is ...

(10^a)/(10^b) = 10^(a-b)

4 0

2 years ago

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

2 years ago

Help. Will give brainliest :)

aleksandrvk [35]

Answer:

18 inches!

Step-by-step explanation:

Since you are multiplying the original size by 3 times (4 in. originally • 3 = 12 inches) you just multiple the original height by 3 (6•3=18)

hope this helped!

7 0

2 years ago

Solve the following inequality.<br> 7(6 - 4n) + 4n > 138

DerKrebs [107]

Answer:

n <−4

42 - 28n + 4n >138

42 - 24n >138

-24n > 138 - 42

-24n >96

n <−96/24

N <−4

7 0

2 years ago