Question

The graph of a quadratic function has a vertex at the point (8,6). It passes through the point (-4,-5). Which of the following equations
represents this function?

Answer 1

Answer:

y= -11/144(x-8)^2+6

Step-by-step explanation:

This equation can be represented in vertex form, which is:  

y=a(x-h)^2+k

If we plug in 8 as h and 6 as k we get the following equation:

y=a(x-8)^2+6

Now we have to plug in x and y. We can use the other point (-4,-5) and plug it into the equation and get:

-5=a(-4-8)^2+6

Once we solve this we get a= -11/144

Now we have to plug in -11/144 into the original equation to get

y = -11/144 (x-8)^2 + 6