Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Answer:
Attachment 1 :- x = 3/2
Attachment 2 :- m + r = 154°
Step-by-step explanation:
Attachment 1 :-

As the base 3 is same on both the sides , cancel the base 3 from both left & right side of eqn. After that we will get:-

Attachment 2 :-
PQR is a straight line . It's given that m + n = 110°
But we know that m + n + r = 180° ..............eqn.1
So substituting the value of m+n in eqn.1 gives :-
m+n+r = 180°
=> r + 110° = 180°
=> r = 180° - 110°
= 70°
It's also given that n+r = 96°
So putting the value of r in the above gives ,
n+r = 96°
=> n + 70° =96°
=> n = 96° - 70°
= 26°
Putting the value of n in eqn.1 gives
m + n = 110°
=> m + 26° = 110°
=> m = 110° - 26°
= 84°
So m + r = 84° + 70° = 154°
ANSWER
My answer is in the photo above
Answer:1.41
Step-by-step explanation: subtraction
Answer:
Please see attachment
Step-by-step explanation:
Please see attachment