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Sveta_85 [38]
3 years ago
14

A girl has 3 shirts (red, yellow, blue) and 6 pairs of socks (red, blue, green, orange, white, black). What is the probability h

er socks and shirt will both be red?
A. 1/12
B. 1/3
C. 1/6
D.1/18
Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0
3 shirts, 1 is red, so the probability of her picking a red shirt is 1/3

6 pairs of socks, 1 pair is red, so probability of picking red would be 1/6

the probability of picking both the red shirt and the red socks would be
1/3 * 1/6 = 1/18

 The answer is D


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SIZIF [17.4K]

Complete question is;

The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?

Answer:

csc θ = -13/12

Step-by-step explanation:

We know that in a unit circle;

(x, y) = (cos θ, sin θ)

Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;

cos θ = -10/26

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Now we want to find csc θ.

From trigonometric ratios, csc θ = 1/sin θ

Thus;

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3 years ago
Help me with this.. thanks
sveta [45]

Answer:

Attachment 1 :-   x = 3/2

Attachment 2 :-  m + r = 154°

Step-by-step explanation:

Attachment 1 :-

9^(^2^-^x^) = 3\\=> 3^2^(^2^-^x^) = 3\\

As the base 3 is same on both the sides , cancel the base 3 from both left & right side of eqn. After that we will get:-

2(2 - x) = 1\\=> 2 - x =\frac{1}{2} \\=> x = 2 - \frac{1}{2} = \frac{3}{2}

Attachment 2 :-

PQR is a straight line . It's given that m + n = 110°

But we know that m + n + r = 180° ..............eqn.1

So substituting the value of m+n in eqn.1 gives :-

m+n+r = 180°

=> r + 110° = 180°

=> r = 180° - 110°

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It's also given that n+r = 96°

So putting the value of r in the above gives ,

n+r = 96°

=> n + 70° =96°

=> n = 96° - 70°

        = 26°

Putting the value of n in eqn.1 gives

m + n = 110°

=> m + 26° = 110°

=> m = 110° - 26°

        = 84°

So m + r = 84° + 70° = 154°

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