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solmaris [256]
3 years ago
11

Please help I don’t get this

Mathematics
1 answer:
mina [271]3 years ago
6 0

Answer:

H = 11m

Step-by-step explanation:

As we know, volume = length * breadth/width * height

Given,

length = 6m

Breadth/width = 3 1/2 or 3.5

Height = ?

So, l * b * h = v

=> 6m * 3.5m * h = 231m

=> 21m * h = 231m

=> h = 231m /21m = 11m

Therefore, height = 11m / 11metres

Hope this helps

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Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 ​ of a blanke
Gnesinka [82]

Answer:


Step-by-step explanation:

Given that Darcie wants to donate minimum 3 blankets to donate to a homeless shelter.  No of days left =60

No of days to complete one blanket = 1/(1/15) = 15 days

Hence in 60 days she has to complete ≥3 blankets

No of days she has to utilize for this will be ≥3(15)=45

No of days she can skip crocheting ≤15

Let x be the no of days crocheted and y no of days skipped

Then x+y≤60

See the graph attached as x axis for days crocheted and y for days skipped

No of blankets can be either 3 or 4.


4 0
3 years ago
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What are the solutions of the equation?
Olegator [25]
The correct answer would be 41
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3 years ago
which statement about the points (2, 5) and (-2, 5) is true plot the points on a coordinate plane to help you answer the questio
iVinArrow [24]

Answer:

A, (2,5) and (-2,5) are reflections of each other on the x axis

5 0
2 years ago
Find the measurements (the length L and the width W) of an inscribed rectangle under the line with the 1st quadrant of the x &am
Leni [432]

The question is incomplete. Here is the complete question.

Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -\frac{3}{4}x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.

Answer: L = 1; W = 9/4; A = 2.25;

Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:

A = x.y

A = x(-\frac{3}{4}.x + 3)

A = -\frac{3}{4}.x^{2}  + 3x

To maximize, we have to differentiate the equation:

\frac{dA}{dx} = \frac{d}{dx}(-\frac{3}{4}.x^{2}  + 3x)

\frac{dA}{dx} = -3x + 3

The critical point is:

\frac{dA}{dx} = 0

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x = 1

Substituing:

y = -\frac{3}{4}x + 3

y = -\frac{3}{4}.1 + 3

y = 9/4

So, the measurements are x = L = 1 and y = W = 9/4

The maximum area is:

A = 1 . 9/4

A = 9/4

A = 2.25

6 0
3 years ago
community group bought 30 tickets to an amusement park at a total cost of $810. They bought x student tickets for $25 each and y
Zina [86]

it would be 18 student tickets and 12 adult tickets

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360+450 = 810

4 0
3 years ago
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