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valina [46]
3 years ago
11

What is the solution to the equation 13.7y = 6.2y + 30? y = –4 y = –1.5 y = 1.5 y = 4

Mathematics
2 answers:
MariettaO [177]3 years ago
7 0

9514 1404 393

Answer:

  y = 4

Step-by-step explanation:

This is a "2-step" equation. Subtract the y-term on the right, then divide by the coefficient of y.

  13.7y = 6.2y +30

  13.7y -6.2y = 6.2y -6.2y +30 . . . . subtract 6.2y

  7.5y = 30 . . . . . simplify

 7.5y/7.5 = 30/7.5 . . . . . . divide by 7.5

  y = 4 . . . . . . . . . simplify

sammy [17]3 years ago
3 0

Answer:

4

Step-by-step explanation:

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35. In a simple random sample of 25 high school students, the sample mean of the SAT scores was 1450, and the sample variance wa
Tatiana [17]

Answer:

1450-2.0\frac{30}{\sqrt{25}}=1450-12    

1450+2.0\frac{30}{\sqrt{25}}=1450+12    

And the best option would be:

c. 1450 +/- 12

Step-by-step explanation:

Information provided

\bar X=1450 represent the sample mean for the SAT scores

\mu population mean (variable of interest)

s^2 = 900 represent the sample variance given

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Solution

The confidence interval for the true mean is given by :

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The sample deviation would be s=\sqrt{900}= 30

The degrees of freedom are given by:

df=n-1=2-25=24

The Confidence is 0.954 or 95.4%, the value of \alpha=0.046 and \alpha/2 =0.023, assuming that we can use the normal distribution in order to find the quantile the critical value would be z_{\alpha/2} \approx 2.0

The confidence interval would be

1450-2.0\frac{30}{\sqrt{25}}=1450-12    

1450+2.0\frac{30}{\sqrt{25}}=1450+12    

And the best option would be:

c. 1450 +/- 12

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