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Leya [2.2K]
2 years ago
8

What is the equation of a line parallel to y=(3)/(4)x-5 and passes through (12,-2)?

Mathematics
1 answer:
Vika [28.1K]2 years ago
3 0

A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.



Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b

-2 = (3/4)*(12) + b

You'll get b= -11

So the equation of the parallel line intersecting the point given is y= 3/4x -11.

I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.

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(B) it would be 9n-10
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Rhett is solving the quadratic equation zero equals X2 minus 2X -3 using the quadratic formula which shows the correct substitut
Alina [70]
X^2-2x -3 =0
a =1 b =-2 and c = -3 

x = - (-2) +/- sqrt (-2)^2 - 4(1)(-3)
      --------------------------------------
                   2(1)

 x = + 2 +/- sqrt [(4) - 4(-3)]
       -------------------------------
                    2

 x = +2 +/- sqrt [4 + 12]
       --------------------------
                   2
x = +2 +/- sqrt[16]
      -------------------
              2

x = +2 +/- (4)
      -------------
             2

x = 2 + 4    or 2 -4 
      -------        ------
         2               2

x = 6/2      or   -2/2

x = 3   or x = -1   
       
8 0
3 years ago
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
PLEASE HURRY WILL GIVE BRAINLIEST A truck can be rented from Company A for $90 a day plus $0.30 per mile. Company B charges $70
arlik [135]
After 40 miles the rental cost for both is the same
4 0
3 years ago
Select all the correct answers.
Phantasy [73]

Answer:

a = 6, b = 8, and c = 10.

Step-by-step explanation:

You can easily use the Pythagorean Theorem to solve all of these.

a = 4; b = 6; c = 8... 4^2 + 6^2 = 16 + 36 = 52. 8^2 = 64. 52 is not equal to 64, so the first choice is not a right triangle.

a = 6; b = 8; c = 10... Well this is a multiple of the 3-4-5 Pythagorean triple, so this is a right triangle.

a = 5; b = 6; c = 761... 5^2 + 6^2 = 25 + 36 = 61. 761^2 = 579121, which is not equal to 61, so the third choice is not a right triangle.

a = 6; b = 9; c = 12... 6^2 + 9^2 = 36 + 81 = 117. 12^2 = 144, which is not equal to 117, so the fourth choice is not a right triangle.

The only case where there is a right triangle is the second choice, where a = 6, b = 8, and c = 10.

Hope this helps!

3 0
3 years ago
Read 2 more answers
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