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3 years ago

Help Me with this math work.

Mathematics

1 answer:

Anna11 [10]3 years ago

8 0

Step-by-step explanation:

-2-2

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Complete the equation so it has infinitely many solutions.

suter [353]

Answer:

im not sure

Step-by-step explanation:

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3 years ago

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Out of 30 problems on the test jose got 4 wrong. What percentage did jose get correct?

dedylja [7]

Jose got 80% correct

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3 years ago

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16. Let W be the set of all vectors in R3 of the form a+2b b -3a Find a basis for Wand state the dimension of W.

Yuki888 [10]

Answer:

$W=\{\left[\begin{array}{ccc}a+2b\\b\\-3a\end{array}\right]: a,b\in\mathbb{R} \}$

Observe that if the vector $x=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ is in W then it satisfies:

$\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]$

This means that each vector in W can be expressed as a linear combination of the vectors $\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]$

Also we can see that those vectors are linear independent. Then the set

$\{\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]\}$ is a basis for W and the dimension of W is 2.

7 0

3 years ago

Rebecca went swimming yesterday. After a while she had covered one fifth of her intended distance. After swimming six more lengt

alukav5142 [94]

Answer:

Option E.

Step-by-step explanation:

Let the intended length of Rebecca's swimming is = x units

and we assume the length of the pool = l units

Now it is given in the question that " She covers one fifth of her intended distance "

That means distance covered = $\frac{x}{5}$

" After swimming six more lengths of the pool she had covered one quarter of her intended distance"

So $\frac{x}{5}+6(l)=\frac{x}{4}$

$6l=\frac{x}{4}-\frac{x}{5}$

$6l=\frac{x}{20}$

x = 20×(6l)

x = 120l

Therefore, Rebecca has to complete 120 lengths of the pool.

Option E is the answer.

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3 years ago

Jason ran 5/7 of the distance around the school track. Sara ran 4/5 of Jason's distance. What fraction of the total distance aro

masha68 [24]

Jason: 5/7
Sara: 4/5

Think of it this way: if the total track is a mile, and Jason runs 5/7 of it, he has run 5/7 of a mile. Then Sara runs 4/5 OF 5/7, with "of" meaning "times," so she runs 4/5 x 5/7, which gives you 20/35, which simplifies to 4/7. You can also think of Sara's distance as 80 percent of Jason's. If she runs "80 percent of the sevenths that Jason ran," that means she ran 4 out of his 5 sevenths.

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3 years ago