Question

Factor the expression over the complex numbers. x^2+72

Answer 1

Answer:

$x^2+72=(x-6i\sqrt{2})(x+6i\sqrt{2})$

Step-by-step explanation:

$x^2+72$

To get the factors , first we solve the given expression for x

$x^2+72=0$

Subtract 72 from both sides

$x^2=-72$

Take square root on both sides

$x=+-\sqrt{-72}$

square root (-1) is 'i'

$x=+-i\sqrt{72}$

$x=+-6i\sqrt{2}$

$x=+6i\sqrt{2}$ and $x=-6i\sqrt{2}$

Write the x values in the parenthesis to get the factor form

When 'a' is a x value then (x-a) is a factor

$x^2+72=(x-6i\sqrt{2})(x+6i\sqrt{2})$

Answer 2

x^2 = -72 so x is $i*6\sqrt{2} or -i*6\sqrt{2}$